问题
It was claimed in Validations in Haskell that use of a Writer
guarantees right-associative concatenation. However, this example seems to show otherwise. What's the correct answer?
{-# LANGUAGE OverloadedStrings #-}
import Control.Monad.Writer
import Data.String
data TM = TMempty
| TMappend TM TM
| TMfromString String
instance IsString TM where
fromString = TMfromString
instance Monoid TM where
mempty = TMempty
mappend = TMappend
instance Show TM where
showsPrec d TMempty = showString "\"\""
showsPrec d (TMfromString s) = showString $ show s
showsPrec d (TMappend a b) = showParen (d > 0) $
showsPrec 1 a .
showString " ++ " .
showsPrec 0 b
theWriter :: Writer TM ()
theWriter = do
tell "Hello"
replicateM_ 2 $ tell "World"
tell "!"
main = print $ execWriter theWriter
Produces:
"Hello" ++ ("World" ++ "World" ++ "") ++ "!"
回答1:
Yes, this is indeed untrue. From the source code:
m >>= k = WriterT $ do
~(a, w) <- runWriterT m
~(b, w') <- runWriterT (k a)
return (b, w `mappend` w')
...
-- | @'tell' w@ is an action that produces the output @w@.
tell :: (Monoid w, Monad m) => w -> WriterT w m ()
tell w = WriterT $ return ((), w)
So the chain of mappend
s will mirror the chain of (>>=)
s.
回答2:
Writer [a]
doesn't guarantee right-associative concatenation, but you can get guaranteed right-associative concatenation with Writer (Endo [a])
.
来源:https://stackoverflow.com/questions/8731858/does-writer-monad-guarantee-right-associative-concatenation