问题
I'm doing something like this:
import pathlib
p = pathlib.Path("temp/").mkdir(parents=True, exist_ok=True)
with p.open("temp."+fn, "w", encoding ="utf-8") as f:
f.write(result)
Error message: AttributeError: 'NoneType' object has no attribute 'open'
Obviously, based on the error message, mkdir
returns None
.
Jean-Francois Fabre suggested this correction:
p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)
with p.open("temp."+fn, "w", encoding ="utf-8") as f:
...
This triggered a new error message:
File "/Users/user/anaconda/lib/python3.6/pathlib.py", line 1164, in open opener=self._opener)
TypeError: an integer is required (got type str)
回答1:
The pathlib module offers an open
method that has a slightly different signature to the built-in open function.
pathlib:
Path.open(mode='r', buffering=-1, encoding=None, errors=None, newline=None)
The built-in:
open(file, mode='r', buffering=-1, encoding=None, errors=None, newline=None, closefd=True, opener=None)
In the case of this p = pathlib.Path("temp/")
it has created a path p
so calling p.open("temp."+fn, "w", encoding ="utf-8")
with positional arguments (not using keywords) expects the first to be mode
, then buffering
, and buffering
expects an integer, and that is the essence of the error; an integer is expected but it received the string 'w'
.
This call p.open("temp."+fn, "w", encoding ="utf-8")
is trying to open the path p
(which is a directory) and also providing a filename which isn't supported. You have to construct the full path, and then either call the path's open method or pass the full path into the open built-in function.
回答2:
You could try:
p = pathlib.Path("temp/")
p.mkdir(parents=True, exist_ok=True)
fn = "test.txt" # I don't know what is your fn
filepath = p / fn
with filepath.open("w", encoding ="utf-8") as f:
f.write(result)
You shouldn't give a string as path. It is your object filepath
which has the method open
.
source
来源:https://stackoverflow.com/questions/47518669/create-new-folder-in-python-with-pathlib-and-write-files-into-it