canEqual() in the scala.Equals trait

问题

From the source code scala/Equals.scala (here):

package scala
trait Equals extends scala.Any {
  def canEqual(that: scala.Any): scala.Boolean
  def equals(that: scala.Any): scala.Boolean
}

In the documentation, it says:

A method that should be called from every well-designed equals method that is open to be overridden in a subclass.

I randomly picked a class which extends scala.Equals and which is simple enough to understand. I picked scala.Tuple2[+T1, +T2], which extends the trait scala.Product[T1, T2], which in turn extends the trait scala.Product, which in turn extends the trait scala.Equals.

Unfortunately, it seems that because scala.Tuple2 is a case class, the canEqual() and equals() methods are automatically generated and therefore could not be found in the source code scala/Tuple2.scala (here).

My questions are:

When is it a good time to extend the trait scala.Equals?
How should canEqual() be implemented?
What are the best practices (or boilerplate) to use canEqual() in equals()?

Thanks in advance!

PS: In case if it matters, I'm using Scala 2.11.7.

回答1:

The canEquals method is used to cover the expectation that equals should be symmetric - that is, if (and only if) a.equals(b) is true, then b.equals(a) should also be true. Problems with this can arise when comparing an instance of a class with an instance of a sub-class. Eg.

class Animal(numLegs: Int, isCarnivore: Boolean) {
  def equals(other: Any) = other match {
    case that: Animal => 
      this.numLegs == that.numLegs && 
      this.isCarnivore == that.isCarnivore
    case _ => false
  }
}

class Dog(numLegs: Int, isCarnivore: Boolean, breed: String) extends Animal(numLegs, isCarnivore) {
  def equals(other: Any) = other match {
    case that: Dog => 
      this.numLegs == that.numLegs && 
      this.isCarnivore == that.isCarnivore &&
      this.breed == that.breed
    case _ => false
  }
}

val cecil = new Animal(4, true)
val bruce = new Dog(4, true, "Boxer")
cecil.equals(bruce) // true
bruce.equals(cecil) // false - cecil isn't a Dog!

To fix this, ensure the two entities are of the same (sub-)type using canEqual in the definition of equals:

class Animal(numLegs: Int, isCarnivore: Boolean) {
  def canEqual(other: Any) = other.isInstanceOf[Animal]
  def equals(other: Any) = other match {
    case that: Animal => 
      that.canEqual(this) &&
      this.numLegs == that.numLegs && 
      this.isCarnivore == that.isCarnivore
    case _ => false
  }
}

class Dog(numLegs: Int, isCarnivore: Boolean, breed: String) extends Animal(numLegs, isCarnivore) {
  def canEqual(other: Any) = other.isInstanceOf[Dog]
  def equals(other: Any) = other match {
    case that: Dog => 
      that.canEqual(this) &&
      this.numLegs == that.numLegs && 
      this.isCarnivore == that.isCarnivore &&
      this.breed == that.breed
    case _ => false
  }
}

val cecil = new Animal(4, true)
val bruce = new Dog(4, true, "Boxer")
cecil.equals(bruce) // false - call to bruce.canEqual(cecil) returns false
bruce.equals(cecil) // false

来源：https://stackoverflow.com/questions/32093526/canequal-in-the-scala-equals-trait

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scala

internals

scala-2.11