Python矩阵逆转与转置

numpy实现

import numpy as np

np.transpose([list])    # 矩阵转置
np.transpose([list]).tolist()    # 矩阵转list

>>> import numpy as np
>>> np.transpose([[1, 2, 3], [1, 2, 3], [1, 2, 3]])
array([[1, 1, 1],
       [2, 2, 2],
       [3, 3, 3]])
>>> np.transpose([[1, 2, 3], [1, 2, 3], [1, 2, 3]]).tolist()
[[1, 1, 1], [2, 2, 2], [3, 3, 3]]

 

矩阵转置

矩阵的转置就是从行变成列, 列变成行

用zip将一系列可迭代对象中的元素打包为元组，之后将这些元组放置在列表中，两步加起来等价于行列转置。

# 矩阵的转置
def transpose(list1):
    return [list(row) for row in zip(*list1)]
 
list1 = [[1, 4], [2, 5], [3, 6]]
print(transpose(list1))  # [[1, 2, 3], [4, 5, 6]]

 

 

# 矩阵逆转
def invert(list1):
    return [row[::-1] for row in list1]
list1 = [[1, 4], [2, 5], [3, 6]]
print(invert(list1))  # [[4, 1], [5, 2], [6, 3]]

矩阵逆转

取出每行的元素，逆序索引遍历 = 左右翻转。

 

来源：CSDN

作者：Lxy_Python

链接：https://blog.csdn.net/Lxy_Python/article/details/83590787