How to get the precision of high_resolution_clock?

问题

C++11 defines high_resolution_clock and it has the member types period and rep. But I can not figure out how I can get the precision of that clock.

Or, if I may not get to the precision, can I somehow at least get a count in nanoseconds of the minimum representable time duration between ticks? probably using period?

#include <iostream>
#include <chrono>
void printPrec() {
    std::chrono::high_resolution_clock::rep x = 1;
    // this is not the correct way to initialize 'period':
    //high_resolution_clock::period y = 1;

    std::cout << "The smallest period is "
              << /* what to do with 'x' or 'y' here? */
              << " nanos\n";
}

回答1:

The minimum representable duration is high_resolution_clock::period::num / high_resolution_clock::period::den seconds. You can print it like this:

std::cout << (double) std::chrono::high_resolution_clock::period::num
             / std::chrono::high_resolution_clock::period::den;

Why is this? A clock's ::period member is defined as "The tick period of the clock in seconds." It is a specialization of std::ratio which is a template to represent ratios at compile-time. It provides two integral constants: num and den, the numerator and denominator of a fraction, respectively.

回答2:

I upvoted R. Martinho Fernandes's answer because I believe it offers the clearest, most straightforward answer to the question. However I wanted to add a little code that showed a little more <chrono> functionality and that addressed this part of the OP's question:

can I somehow at least get a count in nanoseconds of the minimum representable time duration between ticks?

And it is impractical to put this much information into a comment. But I otherwise regard this answer as a supportive comment to R. Martinho Fernandes's answer.

First the code, and then the explanation:

#include <iostream>
#include <chrono>

template <class Clock>
void
display_precision()
{
    typedef std::chrono::duration<double, std::nano> NS;
    NS ns = typename Clock::duration(1);
    std::cout << ns.count() << " ns\n";
}

int main()
{
    display_precision<std::chrono::high_resolution_clock>();
    display_precision<std::chrono::system_clock>();
}

First I created a nanosecond that is using a double as the representation (NS). I used double just in case I needed to show fractions of a nanosecond (e.g. 0.5 ns).

Next, every clock has a nested type named duration. This is a chrono::duration that will have the same std::ratio, and thus the same num and den as pointed out in R. Martinho Fernandes's answer. One of those durations, converted to NS will give us how many nanoseconds in one clock tick of Clock. And that value can be extracted from the duration with the count() member function.

For me this program prints out:

1 ns
1000 ns

回答3:

An std::ratio type representing the tick period of the clock, in seconds.Defined in namespace std::chrono

template<intmax_t Num, intmax_t Denom = 1 > class ratio;

来源：https://stackoverflow.com/questions/8386128/how-to-get-the-precision-of-high-resolution-clock

标签

c++

c++11

clock

duration

chrono