问题
I have an NSMenu
(let's say the Main Menu), with lots of NSMenu
s in it, and NSMenuItem
s at different levels.
I want to be able to get the NSMenuItem instance specifying the tree path (with the title of the corresponding NSMenus/NSMenuItems in it).
Example :
Menu :
- File
- New
- Open
- Document
- Project
- Save
- Save As...
Path : /File/Open/Document
How would you go about it, in the most efficient and Cocoa-friendly way?
回答1:
I think that best way would be to obtain the NSMenuItem
by specifying its title or, better, a custom defined tag.
#define kMenuFileNew 1
#define kMenuFileOpen 2
NSMenu *menu = [[NSMenu alloc] initWithTitle:@"File"];
NSMenuItem *item1 = [[NSMenuItem alloc] initWith..];
item1.tag = kMenuFileOpen;
[menu addItem:item1];
NSMenuItem* item2 = [menu itemWithTag:kMenuFileOpen];
回答2:
So, here it is; solved by creating a Category
on NSMenu
, and using recursion.
Code :
- (NSMenuItem*)getItemWithPath:(NSString *)path
{
NSArray* parts = [path componentsSeparatedByString:@"/"];
NSMenuItem* currentItem = [self itemWithTitle:[parts objectAtIndex:0]];
if ([parts count]==1)
{
return currentItem;
}
else
{
NSString* newPath = @"";
for (int i=1; i<[parts count]; i++)
{
newPath = [newPath stringByAppendingString:[parts objectAtIndex:i]];
}
return [[currentItem submenu] getItemWithPath:newPath];
}
}
Usage :
NSMenuItem* i = [mainMenu getItemWithPath:@"View/Layout"];
来源:https://stackoverflow.com/questions/9852032/getting-nsmenuitem-of-nsmenu-tree-by-title