Getting JSON Exception no value for?

南笙酒味 提交于 2019-12-06 11:19:33
Bernd Linde

Try this code:

if (jsonStr != null) {
  try {

    JSONObject jsonObj = new JSONObject(jsonStr);
   userId = jsonObj.getString("UserId");

  } catch (JSONException e) {
      e.printStackTrace();
}

Your JSON string doesn't have an array in it, so the object that you will be getting from the first JSONObject is already where your information lives.

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