i have a question concerning the boost future continuations. Consider the following code:
#define BOOST_THREAD_PROVIDES_FUTURE
#define BOOST_THREAD_PROVIDES_FUTURE_CONTINUATION
#define BOOST_THREAD_PROVIDES_FUTURE_UNWRAP
#include <boost/thread.hpp>
#include <boost/thread/future.hpp>
#include <boost/date_time/posix_time/posix_time.hpp>
#include <iostream>
boost::future<int> test() {
return boost::async([]() {
for(int i = 0; i < 10; ++i){
boost::this_thread::sleep(boost::posix_time::milliseconds(1000));
}
return 10;});
}
int main(int argc, char *argv[])
//boost::future<int> f1 = test();
boost::future<int> f1 = test().then([](boost::future<int>&& f) {
return test();});
int result = f1.get();
std::cout <<f1.is_ready();
f1.wait();
std::cout<<" "<<f1.is_ready() <<std::endl;
}
In my opinion this should print 1 1
on the commandline. Instead i get 0 0
. Is this the expected behaviour of the continuation?
Commenting out line
boost::future<int> f1 = test().then([](boost::future<int>&& f)
{return test();});
and uncomment line
//boost::future<int> f1 = test();
yields to the expected result.
Tested on g++ 5.2.0
and Visual Studio 2010
with boost-1.57
and boost-1.59
.
Thanks for the help.
来源:https://stackoverflow.com/questions/32046640/boost-future-continuation-never-changes-state