array: convert index of one dimensional array to a vector index of a multidimensional array

▼魔方 西西 提交于 2019-12-06 07:58:40

问题


It will be a long question, please, take a deep breath before reading.

I want to understand what would be the fastest algorithm to convert index of one dimensional array to a vector index of a multidimensional array.

Let's proceed with an example to understand why do I need it:

I have a 2 dimensional array: Array[i1][i2]

i1 runs from i1_b=0 to i1_e=2

i2 runs from i2_b=0 to i2_e=1

So this array is outputted into the file line by line:

Array[0][0]

Array[0][1]

Array[0][2]

Array[1][0]

Array[1][1]

Array[1][2]

Now I read the file line by line and index k is the number of the line being read last.

I read the first line which is Array[0][0] and k=0

I read the second line which is Array[0][1] and k=1

...

One can notice that k will run from k_b=0 to k_e=5 and

k=0 will correspond to i1=0, i2=0

k=1 will correspond to i1=0, i2=1

...

Problem: So my problem is how to convert k into i1 and i2 the fastest way possible? (I don't need it while reading the file, but later in my program)

In this example, one of the solutions would be

i1=k/(i1_e - i1_b + 1);

i2=k%(i1_e - i1_b + 1);

Question 1: Is it the fastest possible solution in term of cycles and computer time?

OK. Question 2: How can we generalize this algorithm to multidimensional arrays?

Array[i1][i2][i3][i4]

i1=k/(i1_e - i1_b + 1);

i2=k%(i1_e - i1_b + 1);

i3=i2/(i1_e - i1_b + 1);

i4=i2%(i1_e - i1_b + 1);

Question 3: Is it the fastest way to do it?

Question 4: related question would be what is the latency for modular division, integer division, adding integers and multiplying integers? If these numbers depend on the architecture, please, also let me know.

Thanks in advance!

P.S. It may be easier for someone to think about this problem as the fastest algorithm to convert seconds into days-hours-minutes-seconds.


回答1:


Question 2: How can we generalize this algorithm to multidimensional arrays?

If you have an array arr[dim_1][dim_2]...[dim_n], you have the equation

k = i_1*(dim_2*...*dim_n) + i_2*(dim_3*...*dim_n) + ... + i_{n-1}*dim_n + i_n
  = i_1*(dim_2*...*dim_n) + r_2

so i_1 = k / (dim_2*..*dim_n) and r_2 = k % (dim_2*...*dim_n), then

i_2 = r_2 / (dim_3*...*dim_n) and r_3 = r_2 % (dim_3*...*dim_n)

etc,

i_j = r_j / (dim_{j+1}*...*dim_n) and r_{j+1} = r_j % (dim_{j+1}*...*dim_n)

until i_n = r_n is found.

Question 3: Is it the fastest way to do it?

If the dimensions are known at compile time, the divisions can be replaced by multiplications, shifts and additions/subtractions. On many architectures, that is faster than a division instruction. On others, not.

But it's only worthwhile thinking about if you're doing a lot of indexing in that array and not much else.

Question 4: related question would be what is the latency for modular division, integer division, adding integers and multiplying integers? If these numbers depend on the architecture, please, also let me know.

These numbers depend on the architecture and processor.




回答2:


please find below how I would implement this in C++1x, I hope this can be useful. Cheers

#include <iostream>
#include <array>
#include <algorithm>


/* stream arrays element by element to ostream */
template<size_t N, typename T>
std::ostream& operator<<(std::ostream& os, std::array<T, N> const&  obj)
{
  os << "{ ";
  for(auto a:obj)std::cout << a << " ";
  std::cout << "}";

  return os;
}

//end of recursion
template<size_t DIM, size_t I>
constexpr typename std::enable_if< (I==DIM), void  >::type
get_indexes(unsigned int index, std::array<unsigned int, DIM> const& depths, std::array<unsigned int,DIM>& indexes)
{}

//begin of the recursion
template<size_t DIM, size_t I=0>
constexpr typename std::enable_if< (I<DIM), void  >::type
get_indexes(unsigned int index, std::array<unsigned int, DIM> const& depths, std::array<unsigned int,DIM>& indexes)
{
    unsigned int  factor    =  1;
    for(unsigned int i=I+1; i<DIM; i++) factor *=depths[i];
    indexes[I]  =  index/factor;
    unsigned int next_index =  index%factor;
    get_indexes<DIM, I+1>(next_index, depths, indexes );
}

//some testing with 3 dimensions 
int main()
{
  constexpr unsigned ndimensions=3;
  std::array<unsigned int, ndimensions> depths{2, 3, 4};
  unsigned int nboxes = 1;

  for(unsigned int i =0; i< ndimensions; i++)nboxes *=depths[i];

  std::array<unsigned int, ndimensions> indexes;

  for(size_t i=0; i<nboxes; i++)
  {

    get_indexes<ndimensions>(i,depths ,  indexes);
    std::cout << i << " -> " <<indexes<< std::endl; 
  }


return 0;
}


来源:https://stackoverflow.com/questions/11586893/array-convert-index-of-one-dimensional-array-to-a-vector-index-of-a-multidimens

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!