问题
I have a file descriptor stored in a variable say var. How can I check whether that descriptor is valid at a later stage?
fdvar1= open(.....);
fdvar2 = fdvar1; // Please ignore the bad design
....
// lots of loops , conditionals and threads. It can call close(fdvar2) also.
....
if(CheckValid(fdvar1)) // How can I do this check ?
write(fdvar1, ....);
Now i want to check whether var1 (which still holds the opened descriptor) is still valid. Any API's for that ?
回答1:
fcntl(fd, F_GETFD) is the canonical cheapest way to check that fd
is a valid open file descriptor. If you need to batch-check a lot, using poll
with a zero timeout and the events
member set to 0 and checking for POLLNVAL
in revents
after it returns is more efficient.
With that said, the operation "check if a given resource handle is still valid" is almost always fundamentally incorrect. After a resource handle is freed (e.g. a fd is close
d), its value may be reassigned to the next such resource you allocate. If there are any remaining references that might be used, they will wrongly operate on the new resource rather than the old one. Thus, the real answer is probably: If you don't already know by the logic of your program, you have major fundamental logic errors that need to be fixed.
回答2:
You can use the fcntl()
function:
int fd_is_valid(int fd)
{
return fcntl(fd, F_GETFD) != -1 || errno != EBADF;
}
回答3:
I don't think there is any function that can tell you if the descriptor is still valid. The descriptor is typically just a small integer like 6 and your libc can choose to reuse that number if you close the file and open a new one later.
Instead, you should consider using dup()
to copy the file descriptor. By duplicating the file descriptor instead of using the same descriptor in multiple places, it might become easier for you to know whether the file descriptor is still valid. You just have to remember to close both the original descriptor and the duplicated one when you are done.
回答4:
From this forum article:
int is_valid_fd(int fd)
{
return fcntl(fd, F_GETFL) != -1 || errno != EBADF;
}
fcntl(GETFL) is probably the cheapest and least likely to fail operation you can perform on a file descriptor. In particular, the specification suggests that it cannot be interrupted by signals, nor is it affected by any sort of lock held anywhere.
回答5:
It seems to me that if you want to know if it still points to the same resource, one (non-perfect) approach would be to fstat()
the descriptor just after open and then later you can do it again and compare the results. Start by looking at .st_mode
& S_IFMT
and go from there -- is it a filesystem object? Look at .st_dev / .st_ino.
Is it a socket? Try getsockname()
, getpeername()
. It won't be 100% certain, but it can tell you if it definitely isn't the same.
回答6:
i solved this problem for me. i don't know whether it can be used for general purpose but for serial connections it works fine (e.g. /dev/ttyUSB0)!
struct stat s;
fstat(m_fileDescriptor, &s);
// struct stat::nlink_t st_nlink; ... number of hard links
if( s.st_nlink < 1 ){
// treat device disconnected case
}
For details see e.g. man page http://linux.die.net/man/2/fstat
Cheers, Flo
来源:https://stackoverflow.com/questions/12340695/how-to-check-if-a-given-file-descriptor-stored-in-a-variable-is-still-valid