问题
I need to integrate an API so I write function:
public function test() {
$client = new GuzzleHttp\Client();
try {
$res = $client->post('http://example.co.uk/auth/token', [
'headers' => [
'Content-Type' => 'application/x-www-form-urlencoded',
],
'json' => [
'cliend_id' => 'SOMEID',
'client_secret' => '9999jjjj67Y0LBLq8CbftgfdreehYEI=',
'grant_type' => 'client_credentials'
]
]);
$res = json_decode($res->getBody()->getContents(), true);
dd($res);
}
catch (GuzzleHttp\Exception\ClientException $e) {
$response = $e->getResponse();
$result = json_decode($response->getBody()->getContents());
return response()->json(['data' => $result]);
}
}
as a responde I got message:
{"data":{"error":"invalid_clientId","error_description":"ClientId should be sent."}}
Now when I try to run the same url with same data in POSTMAN app then I get correct results:
What is bad in my code? I send correct form_params
also I try to change form_params to json but again I got the same error...
How to solve my problem?
回答1:
The problem is that in Postman you're sending the data as a form, but in Guzzle you're passing the data in the 'json'
key of the options array.
I bet that if you would switch the 'json'
to 'form_params'
you would get the result you're looking for.
$res = $client->post('http://example.co.uk/auth/token', [
'form_params' => [
'client_id' => 'SOMEID',
'client_secret' => '9999jjjj67Y0LBLq8CbftgfdreehYEI=',
'grant_type' => 'client_credentials'
]
]);
Here's a link to the docs in question: http://docs.guzzlephp.org/en/stable/quickstart.html#sending-form-fields
Also, I noticed a typo - you have cliend_id
instead of client_id
.
来源:https://stackoverflow.com/questions/49681530/guzzle-laravel-how-to-make-request-with-x-www-form-url-encoded