I am using scala template with input helper.
The class attribute which i use applies style for the <input>
tag.
How do i apply the style specific to the generated <label>
tag?
@inputText(orderItem("item1"),'_label -> "Product*",'_class -> "tinytfss")
Thanks in advance for your support. Manoj
You could try ditching the built-in field constructors and instead write your own. The following template accepts a custom argument that controls the styling of the label:
app/views/_my_field_constructor.scala.html
@(element: helper.FieldElements)
<div class="clearfix @if(element.hasErrors){error}">
<label for="@element.id" class="@element.args.get('_label_class)">@element.label</label>
<div class="input">
@element.input
</div>
</div>
Now use your new field constructor instead of whichever built-in one you were using before:
app/views/form.scala.html
....
@* implicitFieldConstructor = @{ FieldConstructor(twitterBootstrapInput.f) } *@
@implicitField = @{ FieldConstructor(_my_field_constructor.f) }
....
When calling the helper function to create a input text field, you can now pass in a custom _label_class
argument that the template will pick up:
app/views/form.scala.html
@inputText(orderItem("item1"), '_label -> "Product", '_label_class -> "red", '_class -> "tinytfss")
I just ran into this problem myself, but I was able to solve it without using a custom FieldConstructor. All I did was change my form helper line to include a form id, and then reference the label for that form in css. Like so:
scala template file:
<style>
#new-tenant-form label {
font-weight: bold;
}
</style>
. . .
@helper.form(routes.Tenants.create(), 'id -> "new-tenant-form") {
. . .
来源:https://stackoverflow.com/questions/16606042/scala-template-apply-style-to-inputtexts-label-play-2-html5-helper-tag