Comparing strings in PHP the same way MySQL does

问题

I'm storing a varchar in a utf8 MySQL table and using utf8_general_ci collation. I have a unique index on the varchar. I'd like to do a string comparison in PHP that is equivalent to what MySQL will do on the index.

A specific example is that I'd like to be able to detect that 'a' is considered equivalent to 'À' in PHP before this happens:

mysql> insert UniTest (str) values ('a');                                   
Query OK, 1 row affected (0.00 sec)

mysql> insert UniTest (str) values ('À');                                   
ERROR 1062 (23000): Duplicate entry 'À' for key 1

回答1:

The collation has nothing to do with the storage. You need to set the charset to determine the storage encoding. The collation governs how comparison and sorting should happen. The collation must be charset aware, but otherwise it has nothing to do with the charset.

To answer your question, you can use iconv to translitter the text, and then compare it. For example:

function compare($s1, $s2) {
  return strcmp(
    iconv('UTF-8', 'ISO-8859-1//TRANSLIT', $s1),
    iconv('UTF-8', 'ISO-8859-1//TRANSLIT', $s2));
}

This is basically what MySql will do for you, although it's probably faster and it may have a slightly different collation-table than ISO-8859-1//TRANSLIT. Not entirely sure about that.

Would probably be easier to use the database though, as others have already suggested.

回答2:

Why don’t you just let MySQL decide whether there already is a record with the same key?

You could run a SELECT query to ask if there is already a record with this attribute:

SELECT 1
FROM UniTest
WHERE str = "À"

Or you just give it a try inserting the new record and use the functions mysql_error() and mysql_errno() to see if an error occured.

回答3:

Would it be reasonable just to let MySQL do the work, by submitting a query to MySQL like:

SELECT CASE WHEN '$a' = '$b' THEN 1 ELSE 0 END

EDIT post clarification:

You could one-time iterate through the entire character set of interest cartesian joined to itself and build a standard php associative array of equivalence sets.

    for each $char1 in $charset {  
        for each $char2 in $charset {  
            $charmatch[$char1][$char2] = mysqlTestMatch($char1, $char2));  
        }  
    }

Then you'd need to test each string character by character, to see if a) they are the same, or if not, b) they are equivalent.

回答4:

So, if I get it correctly, you want to do a similar compare in PHP as you would get in a check against a UTF-8 General index check in MySQL?

The easiest thing would be to create a helper function that would convert a string according to utf8_general_ci rules used by MySSQL, which is mainly to convert certain letters to a base letter.

The rules for that MySQL collation is listed here:

http://www.collation-charts.org/mysql60/mysql604.utf8_general_ci.european.html

For example, if you scroll down just a bit to the "gold A" on the left, you'll see all the characters that get converted to that A.

Given a helper function, called for example utf8g_to_ascii(), you could write a function:

function utf8_compare($s1, $s2) {
   $a = utf8g_to_ascii($s1);
   $b = utf8g_to_ascii($s2);
   return strcmp( $a, $b );
}

I would model my code after:

http://dev.splitbrain.org/view/darcs/dokuwiki/inc/utf8.php

回答5:

Use intl's Collator or Transliterator.

$s1 = 'a';
$s2 = 'À';

var_dump(
    is_same_string($s1, $s2),
    $s1 === transliterator_transliterate('Any-Latin; Latin-ASCII; Lower()', $s2)
);

function is_same_string($str, $str2, $locale = 'en_US')
{
    $coll = collator_create($locale);
    collator_set_strength($coll, Collator::PRIMARY);  
    return 0 === collator_compare($coll, $str, $str2);
}

来源：https://stackoverflow.com/questions/471021/comparing-strings-in-php-the-same-way-mysql-does

标签

php

mysql

utf-8

collation

mysql-error-1062