问题
I was reading about Inner class in Learning Java. I found this code
class Animal{
class Brain{
}
}
After compiling, javap 'Animal$Brain'
gives output as
Compiled from "Animal.java"class
Animal$Brain {
final Animal this$0;
Animal$Brain(Animal);
}
which explains how the inner class gets the reference to its enclosing instance in the inner class constructor. But when I define the inner class as private like this
class Animal{
private class Brain{
}
}
then after compiling, javap 'Animal$Brain'
gives the output as
Compiled from "Animal.java"
class Animal$Brain {
final Animal this$0;
}
So why is the output different? Why is the inner class constructor not shown? In the latter case also, the inner class is getting the reference of enclosing class instance.
回答1:
Good question. According to this,
If no options are used, javap prints out the package, protected, and public fields and methods of the classes passed to it
Since you have declared Brain
as a private inner class, its default constructor will be implicitly made private and hence it will not be visible outside the Animal
class.
Ref: http://docs.oracle.com/javase/specs/jls/se7/html/jls-8.html#jls-8.8.9
回答2:
By default, javap prints non private members of the classes.
You can use -p option to shows all classes and members.
//javap -p 'Animal$Brain.class'
Compiled from "Animal.java"
class Animal$Brain {
final Animal this$0;
private Animal$Brain(Animal);
}
来源:https://stackoverflow.com/questions/41303833/inner-class-in-java