So, I'm making a bunch of webpages for different communities, and on each I want to have a little weather box that I can customize, just with the name of the town, the current temperature, and the current weather condition. I want to be able to style it all exactly how I want. I found this site called Open Weather Map that seems to do exactly what I want. The problem is that I don't know how to use JSON. It's probably easy, but I seem to have gotten lost on any online tutorials I've tried.
This is an example of a URL for the page, that loads some JSON. http://api.openweathermap.org/data/2.5/weather?q=London,uk
I could just include this in my file and dynamically change the city and the country code to get the city I want. But how do I load this into my weather box? Let's say this is what I have:
<div class="weatherbox">
<strong class="city>{CITY NAME HERE}</strong>
<span class="temperature">{X} °C</span>
<p class="weatherdescription>{WEATHER DESCRIPTION HERE}</p>
</div>
Then how do I access the data from the JSON? I want it to be done as simply as possible. Do I include the file like this to have access to the object, or is it more complicated?
<script type="javascript" src="http://api.openweathermap.org/data/2.5/weather?q=London,uk"></script>
from your line of code:
<script type="javascript" src="http://api.openweathermap.org/data/2.5/weather?q=London,uk"></script>
this is incorrect, the api is returning JSON, it is not a javascript file so you don't access it in such a manner. Note that their API appears to take the city and country as a part of the URL parameters, so this you will need to plug in for the appropriate city/country.
For your specific question you could do something like:
var jsonData;
$(document).ready(function ()
{
$.getJSON('http://api.openweathermap.org/data/2.5/weather?q=London,uk', function(data) {
jsonData = data;
$('.city').text(jsonData.name);
// etc
});
});
See http://jsfiddle.net/jsxm7j3n/1/ for it in action.
Note in order to understand the JSON, you can run it through a JSON parser such as the one at http://json.parser.online.fr/ - this will allow you to better understand the make up of what you're receiving back, and how to parse it.
Double note: forgot to mention this solution uses JQuery - i believe there are purely javascript ways to pull it off, but it will be much more verbose and (in my opinion) harder to understand.
Assuming jQuery:
<script>
// Load the data through ajax, not by including it like a script:
$.get('http://api.openweathermap.org/data/2.5/weather?q=London,uk', function(data) {
$('.weatherbox .temperature').text(data.main.temp);
});
</script>
When you look at the response headers from the URL to the API, it is sending 2 important headers:
Content-Type: application/json; charset=utf-8
Access-Control-Allow-Origin: *
This means:
- Return JSON object, not just a file. You don't have to use
JSON.parse()
or$.getJSON
then. - Allow anyone to request it via ajax (security aspect of Ajax).
Because Ajax by default is async, (that's what the A stands for), you need to wrap your assignment into a function, which is executed after the request has finished.
The following Code runs. You must only change the Api Key
A full Tutorial: https://www.revilodesign.de/blog/sonstiges/wetterdaten-mit-openweathermap-api-in-eigene-webseite-einbinden/
// API URL
var apiUrl = 'https://api.openweathermap.org/data/2.5/weather?q=London,uk&units=metric&APPID=YOUR_API_KEY';
// AJAX
jQuery.ajax ({
url: apiUrl,
type: 'GET',
dataType: 'jsonp',
success: function(data) {
console.log(data);
// COORDINATES
var coordLat = data.coord.lat;
var coordLng = data.coord.lon;
// WEATHER
var weatherId = data.weather[0].id;
var weatherMain = data.weather[0].main;
var weatherDesc = data.weather[0].description;
var weatherIcon = '<img src="https://openweathermap.org/img/w/' + data.weather[0].icon + '.png" />';
var weatherBg = data.weather[0].icon;
// BASE
var baseData = data.base;
// TEMP
var mainTemp = data.main.temp;
var mainPressure = data.main.pressure;
var mainHumidity = data.main.humidity;
var mainTempMin = data.main.temp_min;
var mainTempMax = data.main.temp_max;
// VISIBILITY
var visibility = data.visibility;
// WIND
var windSpeed = data.wind.speed;
var windDeg = data.wind.deg;
// CLOUDS
var clouds = data.clouds.all;
// DT
var dt = data.dt;
// SYS
var sysType = data.sys.type;
var sysId = data.sys.id;
var sysMessage = data.sys.message;
var sysCountry = data.sys.country;
var sysSunrise = data.sys.sunrise;
var sysSunset = data.sys.sunset;
// ID
var id = data.id;
// NAME
var name = data.name;
// COD
var cod = data.cod;
jQuery('#city').html( name );
jQuery('#temp').html( mainTemp + '° C' );
jQuery('#desc').html( weatherDesc );
}
});
#weatherbox {
width: 200px;
height: 20px;
background: #b4ecff;
border-radius: 8px;
display: table;
margin: 20px auto;
text-align: center;
font-size: 14px;
line-height: 20px;
overflow:hidden;
padding: 0 0 10px 0;
}
strong,
span {
width: 100%;
display: inline-block;
padding: 10px 0;
margin: 0;
}
p {
padding: 0;
margin: 0
}
strong {
background: #00769d;
color: #fff;
text-transform: uppercase;
letter-spacing: 1px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="weatherbox">
<strong id="city"></strong>
<span id="temp"></span>
<p id="desc"></p>
</div>
来源:https://stackoverflow.com/questions/27639668/open-weather-api