Python AppIndicator bindings -> howto check if the menu is open?

问题

Here is a minimal example of an AppIndicator:

#!/usr/bin/python

import gobject
import gtk
import appindicator

if __name__ == "__main__":
    ind = appindicator.Indicator("example-simple-client", "gtk-execute", appindicator.CATEGORY_APPLICATION_STATUS)
    ind.set_status (appindicator.STATUS_ACTIVE)
    menu = gtk.Menu()
    menu_items = gtk.MenuItem('Quit')
    menu.append(menu_items)
    menu_items.connect("activate", gtk.main_quit)
    menu_items.show()
    ind.set_menu(menu)
    gtk.main()

Unfortunately the documentation on this is very incomplete. What I'm looking for is a way to check if the AppIndicator menu was opend by the user (e.g. the indicator icon was clicked). So is there a signal, that is emitted when the menu is opened?

回答1:

It looks like the answer is no unfortunately.

print gobject.signal_list_names(ind)
('new-icon', 'new-attention-icon', 'new-status', 'new-label', 'x-ayatana-new-label', 'connection-changed', 'new-icon-theme-path')

I tried all of them and none of them appear to activate when the indicator is clicked. For what it's worth the unity devs seem to want to keep all indicators behaving in a uniform way, so it's quite possible that it's deliberately limited.

回答2:

There is a bug filed about it on Launchpad https://bugs.launchpad.net/screenlets/+bug/522152

Notice that "activate" signal is available for AppIndicator submenus.

来源：https://stackoverflow.com/questions/7063743/python-appindicator-bindings-howto-check-if-the-menu-is-open