Java DecimalFormat Scientific Notation Question

穿精又带淫゛_ 提交于 2019-12-05 10:49:43

Here's one way. Hokey, perhaps, but it works...

public class DecimalFormatTest extends TestCase {
    private static class MyFormat extends NumberFormat {
        private final DecimalFormat decimal;

        public MyFormat(String pattern) {
            decimal = new DecimalFormat(pattern);
        }

        public StringBuffer format(double number, StringBuffer toAppendTo, FieldPosition pos) {
            StringBuffer sb = new StringBuffer();
            sb.append(modified(Math.abs(number) > 1.0, decimal.format(number, toAppendTo, pos).toString()));
            return sb;
        }

        private String modified(boolean large, String s) {
            return large ? s.replace("E", "E+") : s;
        }

        public StringBuffer format(long number, StringBuffer toAppendTo, FieldPosition pos) {
            StringBuffer sb = new StringBuffer();
            sb.append(modified(true, decimal.format(number, toAppendTo, pos).toString()));
            return sb;
        }

        public Number parse(String source, ParsePosition parsePosition) {
            return decimal.parse(source, parsePosition);
        }

        public void setPositivePrefix(String newValue) {
            decimal.setPositivePrefix(newValue);
        }
    }
    private MyFormat    format;

    protected void setUp() throws Exception {
        format = new MyFormat("0.0E0");
        format.setPositivePrefix("+");
    }

    public void testPositiveLargeNumber() throws Exception {
        assertEquals("+1.0E+2", format.format(100.0));
    }

    public void testPositiveSmallNumber() throws Exception {
        assertEquals("+1.0E-2", format.format(0.01));
    }

    public void testNegativeLargeNumber() throws Exception {
        assertEquals("-1.0E+2", format.format(-100.0));
    }

    public void testNegativeSmallNumber() throws Exception {
        assertEquals("-1.0E-2", format.format(-0.01));
    }
}

Alternatively you could subclass DecimalFormat, but I find it generally cleaner not to subclass from concrete classes.

Enrico Scantamburlo

This worked form me,

DecimalFormatSymbols SYMBOLS = DecimalFormatSymbols.getInstance(Locale.US);

    if (value > 1 || value < -1) {
        SYMBOLS.setExponentSeparator("e+");
    } else {
        SYMBOLS.setExponentSeparator("e");
    }

    DecimalFormat format = new DecimalFormat(sb.toString(), SYMBOLS);
Grant Wagner

Could you use printf() instead:

Format format = new DecimalFormat("0.0E0");
Double d = new Double(.01);
System.out.println(format.format(d));
System.out.printf("%1.1E\n", d);
d = new Double(100);
System.out.println(format.format(d));
System.out.printf("%1.1E\n", d);

Output:

1.0E-2
1.0E-02
1.0E2
1.0E+02

If you need to output to a String instead, you can use the information provided at Formatted Printing for Java (sprintf) to do that.

EDIT: Wow, that PrintfFormat() thing is huge and seems to be unnecessary:

OutputStream b = new ByteArrayOutputStream();
PrintStream p = new PrintStream(b);
p.printf("%1.1E", d);
System.out.println(b.toString());

I got the idea for the above code from Get an OutputStream into a String.

How to use?
See formatTest method.

if (value.compareTo(positive) == 1 || value.compareTo(negative) == -1) is useful for very large numbers

/**
 * inspired by:<br>
 * https://stackoverflow.com/a/13065493/8356718
 * https://stackoverflow.com/a/18027214/8356718
 * https://stackoverflow.com/a/25794946/8356718
 */
public static String format(String number, int scale) {
    BigDecimal value = new BigDecimal(number);
    DecimalFormatSymbols symbols = DecimalFormatSymbols.getInstance(Locale.US);
    BigDecimal positive = new BigDecimal(1);// scale is zero
    positive.setScale(0);// unnecessary
    BigDecimal negative = new BigDecimal(-1);// scale is zero
    negative.setScale(0);// unnecessary
    if (value.compareTo(positive) == 1 || value.compareTo(negative) == -1) {
        symbols.setExponentSeparator("e+");
    } else {
        symbols.setExponentSeparator("e");
    }
    DecimalFormat formatter = new DecimalFormat("0.0E0", symbols);
    formatter.setRoundingMode(RoundingMode.HALF_UP);
    formatter.setMinimumFractionDigits(scale);
    return formatter.format(value);
}

/**
 * set the scale automatically
 */
public static String format(String number) {
    BigDecimal value = new BigDecimal(number);
    return format(number, value.scale() > 0 ? value.precision() : value.scale());
}

/*
output:
----------
0e0
1.0e-2
-1.0e-2
1.234560e-5
-1.234560e-5
1e0
-1e0
3e+0
-3e+0
2e+2
-2e+2
----------
0.0000000000e0
1.0000000000e-2
-1.0000000000e-2
1.2345600000e-5
-1.2345600000e-5
1.0000000000e0
-1.0000000000e0
3.0000000000e+0
-3.0000000000e+0
2.0000000000e+2
-2.0000000000e+2
----------
*/
public static void formatTest() {
    System.out.println("----------");
    System.out.println(format("0"));
    System.out.println(format("0.01"));
    System.out.println(format("-0.01"));
    System.out.println(format("0.0000123456"));
    System.out.println(format("-0.0000123456"));
    System.out.println(format("1"));
    System.out.println(format("-1"));
    System.out.println(format("3"));
    System.out.println(format("-3"));
    System.out.println(format("200"));
    System.out.println(format("-200"));
    System.out.println("----------");
    System.out.println(format("0", 10));
    System.out.println(format("0.01", 10));
    System.out.println(format("-0.01", 10));
    System.out.println(format("0.0000123456", 10));
    System.out.println(format("-0.0000123456", 10));
    System.out.println(format("1", 10));
    System.out.println(format("-1", 10));
    System.out.println(format("3", 10));
    System.out.println(format("-3", 10));
    System.out.println(format("200", 10));
    System.out.println(format("-200", 10));
    System.out.println("----------");
}

Why not use "0.0E+0" pattern instead? Note the plus sign before last zero.

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