C#二位数组 数组矩阵对角线之和

二维数组：

        public static void Main(string[] args)
        {

            int[,] a = new int[3, 3];
            Random rom = new Random();
            for (int x = 0; x < a.GetLength(0); x++)
            {
                for (int y = 0; y < a.GetLength(1); y++)
                {
                    a[x, y] = rom.Next(31);
                    Console.Write("{0} ", a[x, y]);
                }
                Console.WriteLine("");
            }
        }

 

    //  求矩阵对角线之和

   public static void Main(string[] args)        {            int[,] a= new int[3, 3];            Random rnd = new Random();            int a1 = 0;            int a2 = 0;            for (int x = 0; x < a.GetLength(0); x++)            {                for (int y = 0; y < a.GetLength(1); y++)                {                    a[x, y] = rnd.Next(21);                    Console.Write("{0}  ", a[x, y]);                    if (x == y)                    {                        a1 += a[x, y]; //统计正对角线元素之和                    }                    if (x + y == a.GetLength(0) - 1)                    {                        a2 += a[x, y]; //统计副对角线元素之和                    }                }                Console.WriteLine("");            }            Console.WriteLine("正对角线元素之和：{0}", a1);            Console.WriteLine("副对角线元素之和：{0}", a2);        }

 

来源：https://www.cnblogs.com/yijieyufu/p/11902017.html