Symfony 4, get the root path of the project from a custom class (not a controller class)

问题

In the src/Utils directory, I created a custom class Foo for various things. I'm looking for a way to get the absolute root path of the symfony 4 project

From a controller, its easy with :

$webPath = $this->get('kernel')->getProjectDir();

But from a custom class I created in my src/Utils directory, how can I get the root path directory ?

I could pass the path from the controller to the Foo class :

$webPath = $this->get('kernel')->getProjectDir();
$faa = new Foo($webPath);
$faa->doSomething();

but I think its more proper to store this information in the Foo class and have only "controller logic" in the controller class

回答1:

In Symfony AppKernel class is handling the project root directory under method getProjectDir(). To get it in the controller you can do:

$projectRoot = $this->get('kernel')->getProjectDir();

it will return you a project root directory.

If you need the project root directory in one of your classes you have two choices which I will present to you. First is passing AppKernel as dependency:

class Foo 
{
    /** KernelInterface $appKernel */
    private $appKernel;

    public function __construct(KernelInterface $appKernel)
    {
        $this->appKernel = $appKernel;
    }
}

Thanks to Symfony 4 autowiring dependencies it will be autmomaticaly injeted into your class and you could access it by doing:

$this->appKernel->getProjectDir();

But please notice: I don't think it's a good idea, until you have real need and more to do with AppKernel class than getting the project root dir. Specially if you think later on creating about unit tests for your class. You would automatically increase complexity by having a need to create mock of AppKernel for example.

Second option and IMHO better would be to pass only a string with path to directory. You could achieve this by defining a service inside config/services.yaml like this:

services:
    (...)
    MyNamespace\Foo:
        arguments:
            - %kernel.project_dir%

and your constructor would look like:

class Foo 
{
    /** string $rootPath */
    private $rootPath;

    public function __construct(string $rootPath)
    {
        $this->rootPath = $rootPath;
    }
}

回答2:

This is work :

// from Foo class
use Symfony\Component\HttpKernel\KernelInterface;
...
class Foo{
    private $rootDir;
    public function __construct(KernelInterface $kernel)
    {
        $this->rootDir = $kernel->getProjectDir();
    }
    public function myfoomethod(){
        return $this->getRootDir();
    }
    public function getRootDir(){
        return $this->rootDir;
    }
}


// from the controller class 
use App\Utils\Foo;
...
class FaaController extends AbstractController
{
    /**
     * @Route("/scenario", name="scenario")
     */
    public function new(Foo $foo)
    {
        dump($foo->myfoomethod()); //show the dir path !
        return $this->render('faa/index.html.twig');
    }
}

来源：https://stackoverflow.com/questions/52850493/symfony-4-get-the-root-path-of-the-project-from-a-custom-class-not-a-controlle

标签

php

symfony4