1. WSL ubuntu16 安装
略
2. 安装SQLAdvisor
1、拉代码
git clone https://github.com/Meituan-Dianping/SQLAdvisor
或者下载在解压
2、装依赖
apt-get install cmake libaio-dev libffi-dev apt-get install libglib2.0-dev #先装percona软件源 https://www.percona.com/doc/percona-server/5.6/installation/apt_repo.html wget https://repo.percona.com/apt/percona-release_latest.$(lsb_release -sc)_all.deb dpkg -i percona-release_latest.$(lsb_release -sc)_all.deb apt-get update apt-get install libperconaserverclient18.1-dev apt-get install g++
3、编译依赖项sqlparser
cmake -DBUILD_CONFIG=mysql_release -DCMAKE_BUILD_TYPE=debug -DCMAKE_INSTALL_PREFIX=/usr/local/sqlparser ./ make && make install
4、安装SQLAdvisor
cd sqladvisor/ cmake -DCMAKE_BUILD_TYPE=debug ./ make #报错: /usr/include/glib-2.0/glib/gtypes.h:32:24: fatal error: glibconfig.h: No such file or directory #处理报错 sudo find ./ iname "glibconfig.h" 2>/dev/null /usr/lib/x86_64-linux-gnu/glib-2.0/include/glibconfig.h #修改 CMakeLists.txt #include_directories("/usr/lib64/glib-2.0/include") #依据find的路径修改为下面 include_directories("/usr/lib/x86_64-linux-gnu/glib-2.0/include") #重新编译 rm CMakeCache.txt cmake -DCMAKE_BUILD_TYPE=debug ./ make
3. 使用和测试
1、使用
# sqladvisor --help 用法: sqladvisor [OPTION…] sqladvisor SQL Advisor Summary 帮助选项: -?, --help 显示帮助选项 应用程序选项: -f, --defaults-file sqls file -u, --username username -p, --password password -P, --port port -h, --host host -d, --dbname database name -q, --sqls sqls -v, --verbose 1:output logs 0:output nothing #使用,注意传参空格 ./sqladvisor -h xx -P xx -u xx -p 'xx' -d xx -q "sql" -v 1
$> cat sql.cnf [sqladvisor] username=xx password=xx host=xx port=xx dbname=xx sqls=sql1;sql2;sql3.... cmd: ./sqladvisor -f sql.cnf -v 1
2、测试
aijie@DESKTOP-N85GQN8:~/dbplat/SQLAdvisor-master/sqladvisor$ ./sqladvisor -u ajtest -p ajtest -h 127.0.0.1 -P 3306 -d ajtest -q "select * from t1 where name = 'ccc';" -v 1 2019-05-15 16:41:28 14792 [Note] 第1步: 对SQL解析优化之后得到的SQL:select `*` AS `*` from `ajtest`.`t1` where (`name` = 'ccc') 2019-05-15 16:41:28 14792 [Note] 第2步:开始解析where中的条件:(`name` = 'ccc') 2019-05-15 16:41:28 14792 [Note] show index from t1 2019-05-15 16:41:28 14792 [Note] show table status like 't1' 2019-05-15 16:41:28 14792 [Note] select count(*) from ( select `name` from `t1` FORCE INDEX( PRIMARY ) order by id DESC limit 1) `t1` where (`name` = 'ccc') 2019-05-15 16:41:28 14792 [Note] 第3步:表t1的行数:2,limit行数:1,得到where条件中(`name` = 'ccc')的选择度:1 2019-05-15 16:41:28 14792 [Note] 第4步:表t1 的SQL太逆天,没有优化建议 2019-05-15 16:41:28 14792 [Note] 第5步: SQLAdvisor结束!
来源:https://www.cnblogs.com/jesper/p/10870508.html