how use EOF stdin in C | 易学教程

问题

I need to input coordinates into an array until EOF is encountered, but something is wrong in my code. I used ctrl+Z, ctrl+D

int main()
{
    int x[1000],y[1000];
    int n=0,nr=0,a,b,i;
    printf("Enter the coordinates:\n");
    while(scanf ( "%d %d ", &a, &b) == 2)
    {
     x[n]=a;
     y[n]=b;
     n++;
    }
    if (!feof(stdin))
    {
       printf("Wrong\n");
    }
    else
    {
       for(i=0;i<n;i++)
       printf("%d %d\n", x[i], y[i]);
    }

  return 0;
}

回答1:

I suggest using

while(!feof(stdin) && scanf ( "%d %d ", &a, &b) == 2)

and actually it is better to test feof after (not before!) some input operation, so:

while (scanf("%d %d ", &a, &b) == 2 && !feof(stdin))

BTW, on many systems stdin is line buffered, at least with interactive terminals (but perhaps not when stdin is a pipe(7)), see setvbuf(3)

On Linux & POSIX you might consider reading every line with getline(3) (or even with readline(3) if reading from the terminal, since readline offers editing abilities), then parsing that line with e.g. sscanf(3) (perhaps also using %n) or strtol(3)

回答2:

The only real problem that I see in your code is the extra spaces in the scanf format string. Those spaces tell scanf to consume whitespace character on the input, which makes scanf not return to your code until it hits a non-whitespace character (such as a letter, a number, punctuation, or EOF).

The result is that after typing two numbers and then Enter, you have to type Ctrl-D (Ctrl-Z in DOS/Windows) twice before your program escapes the while loop.

来源：https://stackoverflow.com/questions/8094702/how-use-eof-stdin-in-c

标签

stdin

scanf

feof