Tune method in Controller. [PersistenceUnit: default] Unable to build Hibernate SessionFactory

Question

how to realize the idea? Send me information: {"idBanner":2, "fullnameClient":"Aria"}. If click don't contain in database, then click save and send email businesscenter. Else, send a message: "you responsed". Error maybe version dependences? (Entity) : Click bind Banner, Banner bind Businesscentr.

Answer 1

Schema-validation: wrong column type encountered in column [id_bc] in table [banner]; found [int (Types#INTEGER)], but expecting [bigint (Types#BIGINT)]

This is the problem which is causing this

Stack trace it is mention that hibernate is validating your schema where it is finding wrong column type, this happen when hibernate.hbm2ddl.auto = validate ,

Now you can keep this property hibernate.hbm2ddl.auto = update , so that it will update the changes made in your entities,

or just change your database schema and make the type of this column as big integer, as in your entities you are using long.

Also, no need to recreate database when you are using hibernate.hbm2ddl.auto = update hibernate won't validate your schema in this case.

Thanks.

Answer 2

Remade database, changed in hibernate.hbm2ddl.auto = create