How do I set a UInt32 to it's maximum value

Question

1. What is the maximum value for a UInt32?

2. Is there a way I can use the sizeof operator to get the maximum value (as it is unsigned)? So I don't end up with #defines or magic numbers in my code.

Answer 1

There's a macro UINT32_MAX defined in stdint.h which you can use

#include <stdint.h>

uint32_t max = UINT32_MAX;

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More about the relevant header <stdint.h>:

http://pubs.opengroup.org/onlinepubs/009695299/basedefs/stdint.h.html

Answer 2

The maximum value for UInt32 is 0xFFFFFFFF (or 4294967295 in decimal).

sizeof(UInt32) would not return the maximum value; it would return 4, the size in bytes of a 32 bit unsigned integer.

Answer 3

Just set the max using standard hexadecimal notation and then check it against whatever you need. 32-bits is 8 hexadecimals bytes, so it'd be like this:

let myMax: UInt32 = 0xFFFFFFFF

if myOtherNumber > myMax {
    // resolve problem
}

Answer 4

The portable way:

std::numeric_limits<uint32_t>::max()

Answer 5

An alternative for any unsigned in C or C++ is:

anUnsigned = -1;

This is useful since it works for them all, so if you change from unsigned int to unsigned long you don't need to go through your code. You will also see this used in a lot of bit fiddling code:

anUnsigned |= -(aBoolOrConditionThatWhenTrueCausesAnUnsignedToBeSetToAll1s)
anUnsigned |= -(!aValueThatWhenZeroCausesAnUnsignedToBeSetToAll1s)
anUnsigned |= -(!!aValueThatWhenNonZeroCausesAnUnsignedToBeSetToAll1s)

The downside is that it looks odd, assigning a negative number to an unsigned!

Answer 6

4.294.967.295 is the maximal value or in hexadecimal 0xFFFFFFFF