Convert .csv file into Excel in VBScript

Question

I'm writing a program to convert a .csv file into an Excel file in VBScript.

This is the portion of my .csv file (It has a header as well)

Report Title,Goods Performance Characteristics Report,,Report Title,Goods Performance Characteristics Report,,,,,,, Begin Date,8/7/2012,,,,,,,,,, Template Name,XXXX-Test-VVV-Two-Positions,,,,,,,,,, Total Productions,,,,,,,,,,,

,ID,Name,Product Description,Issue Date,Product Type,Weight (kg),Weight (lb),Price,Product volume, Profit,Total Value (000) ,315616102,Lux Honey,Body Wash,8/1/2012,C,0.06,0.06,93,793920,0,7455703038 ,579780206,Clear AntiDandruf,Shampoo,8/1/2012,C,0.06,0.06,60.5,1325980,2.05,8022179000 ,761713106,Loreal Divine,Face Crub,8/1/2012,F,0.12,0.12,46.52,3314780,5.07,15420356560

This is the updated VBScript code I wrote for the conversion.

Dim xlApp, workBook1, workBook2,aSheets, fileName, aInfo2,aInfo1,oExcel
  Const XlPlatform = "xlWindows"
  Const xlDelimited = 1
  Const xlTextQualifierDoubleQuote = 1
  Const xlTextFormat = 2
  Const xlGeneralFormat = 1


  Set oExcel = Sys.OleObject("Excel.Application")  
  Set xlApp = CreateObject("Excel.Application")  

  Set workBook1 = xlApp.ActiveWorkBook

  Set workBook1 = xlApp.WorkBooks.OpenText("Y:\Personal Folders\XXXX\TestFile1.csv",XlPlatform, 1, xlDelimited, xlTextQualifierDoubleQuote, true, false, false, true, false, true, "CRLF", Array(Array (1,2),Array (2,2),Array (3,2),Array (4,1),Array (5,2),Array (6,1),Array (7,1),Array (8,1),Array (9,1),Array (10,1),Array (11,1)), true, false)

  Set workBook1 = xlApp.ActiveWorkBook
  xlApp.Visible = true

  workBook1.Save "Y:\Personal Folders\XXXX\x.xlsx", xlNormal
  workBook1.Close

But the data is not in a tabular form in the Excel file.I want to display the data in a tabular form.

Could anyone please help me to extract data based on the delimeters.I need the header part in the excel file as well.

Thanks in advance

Answer 1

There are several issues with the code from your updated question:

• Const XlPlatform = "xlWindows"

  XlPlatform must be a numeric value, not a string. The xlWindows member of the enumeration has the value 2. However, since that's the default anyway, you can simply omit this value when calling OpenText.

• Set workBook1 = xlApp.ActiveWorkBook

  A newly spawned Excel instance doesn't have an active workbook, so it's pointless to assign that to a variable before you actually open or create a workbook.

• Set workBook1 = xlApp.WorkBooks.OpenText(...)

  The OpenText method does not return an object, so there's nothing to assign in the above statement.

• ...ooks.OpenText(..., true, "CRLF", ...)

  The string "CRLF" is not a character. Why do you want to specify line-breaks as separator-characters anyway?

• ..., Array(...), true, false)

  The last 2 parameters you specified are TextVisualLayout (specifies left-to-rigt/right-to-left) and DecimalSeparator. Both of them are not boolean values. Simply omit them if you don't know for certain that you need them.

• workBook1.Save "Y:\Personal Folders\XXXX\x.xlsx", xlNormal

  The Save method saves a workbook under its current name. To save a workbook under a different name you must use the SaveAs method. The constant xlNormal isn't defined anywhere in your code. Plus, xlNormal produces an Excel 97/2003 workbook (.xls). To save a workbook as an Excel 2007/2010 workbook (.xlsx) you must use the xlOpenXMLWorkbook constant.

The following code worked for me:

Const xlDelimited                =  1
Const xlTextQualifierDoubleQuote =  1
Const xlOpenXMLWorkbook          = 51

Set xl = CreateObject("Excel.Application")

xl.Workbooks.OpenText "Y:\Personal Folders\XXXX\TestFile1.csv", , , xlDelimited _
  , xlTextQualifierDoubleQuote, True, False, False, True, False, False, _
  , Array(Array(1,2), Array(2,2), Array(3,2), Array(4,1), Array(5,2) _
  , Array(6,1), Array(7,1), Array(8,1), Array(9,1), Array(10,1), Array(11,1))
Set wb = xl.ActiveWorkbook

wb.SaveAs "Y:\Personal Folders\XXXX\x.xlsx", xlOpenXMLWorkbook, , , , False
wb.Close

xl.Quit

Answer 2

I'm using Excel 2003.The following is a code I got to specify the .csv file format

Set xl = CreateObject("Excel.Application")

Set wb = xl.Workbooks.OpenText "input.csv", , , xlDelimited, xlDoubleQuote, _
  False, False, True, , , , dataTypes

from Vbscript to import csv into excel

Could you please explain the function of the following line?

Set wb = xl.Workbooks.OpenText "input.csv", , , xlDelimited, xlDoubleQuote, _
      False, False, True, , , , dataTypes

My implementation of the OpenText property for the above mentioned .csv file

Set workBook1 = xlApp.WorkBooks.OpenText("D:\Personal Folders\XXXX\TestFile1.csv", , ,xlDelimited, ,false ,false ,false ,True,false ,false ,"~")

Answer 3

You need to specify what Format you are saving as. The following will specify it as a standard .xls for 2003

    Workbooks.Open Filename:= _
    "D:\Personal Folders\XXXXX\TestFile1.csv"

    ActiveWorkbook.SaveAs Filename:= _
    "D:\Personal Folders\XXXXX\x.xls", FileFormat:=xlNormal

    ActiveWorkbook.Close

Also can try

ActiveWorkbook.SaveAs Filename:= _
    "D:\Personal Folders\XXXXX\x.xls", FileFormat:= 56