问题
So I have a function that keeps skipping over the first getline and straight to the second one. I tried to clear the buffer but still no luck, what's going on?
void getData(char* strA, char* strB)
{
cout << "Enter String 1: "; // Shows this line
cin.clear();
cin.getline(strA, 50); // 50 is the character limit, Skipping Input
cout << endl << "Enter String 2: "; // Showing This Line
cin.clear();
cin.getline(strB, 50); // Jumps Straight to this line
}
回答1:
Make sure you didn't use cin >> str
. before calling the function. If you use cin >> str
and then want to use getline(cin, str)
, you must call cin.ignore()
before.
string str;
cin >> str;
cin.ignore(); // ignores \n that cin >> str has lefted (if user pressed enter key)
getline(cin, str);
In case of using c-strings:
char buff[50];
cin.get(buff, 50, ' ');
cin.ignore();
cin.getline(buff, 50);
ADD: Your wrong is not probably in the function itself, but rather before calling the function. The stream cin
have to read only a new line character \n'
in first cin.getline
.
回答2:
cin.clear();
clears any error bits on the stream - it does not consume any data that may be pending.
You want to use cin.ignore()
to consume data from the stream.
回答3:
After you read something there is still 'RETURN' character inside bufor so you have to cin.ignore()
after each read.
You can also use cin.sync()
to clear the stream.
Actualy clear method only clears flags.
There is also option that you can go to the end of stream, with nothing left to read you should write without problems.
std::cin.seekg(0, std::ios::end);
It is up to you what will you use.
回答4:
use cin.ignore(-1);
It will not remove the first character of the input string
来源:https://stackoverflow.com/questions/12186568/getline-skipping-first-even-after-clear