问题
I am using Scikit-learning and I need to calculate the True positive (TP), the False Positive (FP), the True Negative (TN) and the False Negative (FN) from a confusion matrix like this:
[[2 0 3 4]
[0 4 5 1]
[1 0 3 2]
[5 0 0 4]]
I know how to calculate the TP, the FP and the FN but I don't know how to get the TN. Can someone tell me?
回答1:
I think you should treat this multi-class classification in a one-vs-the-rest manner (so each 2x2 table i
measures the performance of a binary classification problem that whether each obs belongs to label i
or not). Consequently, you can calculate the TP, FP, FN, TN for each individual label.
import numpy as np
confusion_matrix = np.array([[2,0,3,4],
[0,4,5,1],
[1,0,3,2],
[5,0,0,4]])
def process_cm(confusion_mat, i=0, to_print=True):
# i means which class to choose to do one-vs-the-rest calculation
# rows are actual obs whereas columns are predictions
TP = confusion_mat[i,i] # correctly labeled as i
FP = confusion_mat[:,i].sum() - TP # incorrectly labeled as i
FN = confusion_mat[i,:].sum() - TP # incorrectly labeled as non-i
TN = confusion_mat.sum().sum() - TP - FP - FN
if to_print:
print('TP: {}'.format(TP))
print('FP: {}'.format(FP))
print('FN: {}'.format(FN))
print('TN: {}'.format(TN))
return TP, FP, FN, TN
for i in range(4):
print('Calculating 2x2 contigency table for label{}'.format(i))
process_cm(confusion_matrix, i, to_print=True)
Calculating 2x2 contigency table for label0
TP: 2
FP: 6
FN: 7
TN: 19
Calculating 2x2 contigency table for label1
TP: 4
FP: 0
FN: 6
TN: 24
Calculating 2x2 contigency table for label2
TP: 3
FP: 8
FN: 3
TN: 20
Calculating 2x2 contigency table for label3
TP: 4
FP: 7
FN: 5
TN: 18
回答2:
I think for a multiclass problem like this you have to decide which one of these 4 classes can be considered positive and you have to combine rest 3 as negative to calculate true negative.A detailed discussion was done here.
来源:https://stackoverflow.com/questions/31345724/scikit-learn-how-to-calculate-the-true-negative