Python set Parallel Port data pins high/low

Question

I am wondering how to set the data pins on a parallel port high and low. I believe I could use PyParallel for this, but I am unsure how to set a specific pin.

Thanks!

Answer 1

You're talking about a software-hardware interface here. They are usually set low and high by assigning a 1-byte value to a register. A parallel port has 8 pins for data to travel across. In a low level language like C, C++, there would be a register, lets call it 'A', somewhere holding 8 bits corresponding to the 8 pins of data. So for example:

Assuming resgister A is setup like pins: [7,6,5,4,3,2,1,0]

C-like pseudocode

A=0x00 // all pins are set low
A=0xFF // all pins are high
A=0xF0 // Pins 0:3 are low, Pins 4:7 are high

This idea follows through with PyParallel

import parallel
p = parallel.Parallel() # open LPT1
p.setData(0x55) #<--- this is your bread and butter here  

p.setData is the function you're interested in. 0x55 converted to binary is

0b01010101

-or-

[L H L H L H L H]

So now you can set the data to a certain byte, but how would I sent a bunch of data... lets say 3 bytes 0x00, 0x01, 0x02? Well you need to watch the ack line for when the receiving machine has confirmed receipt of whatever was just sent.

A naive implementation:

data=[0x00, 0x01, 0x02]
while data:
    onebyte=data.pop()
    p.setDataStrobe('low') #signal that we're sending data
    p.setData(onebyte)
    while p.getInAcknowledge() == 'high': #wait for this line to go 'low'
                                          # to indicate an ACK
        pass                              #we're waiting for it to acknowledge...
    p.setDataStrobe('high')#Ok, we're done sending that byte.

Ok, that doesn't directly answer your question. Lets say i ONLY want to set pin 5 high or low. Maybe I have an LED on that pin. Then you just need a bit of binary operations.

portState = 0b01100000 #Somehow the parallel port has this currently set
newportState = portState | 0b00010000#<-- this is called a bitmask
print newportState 
>>> 0b011*1*0000

Now lets clear that bit...

newportState = 0b01110000
clearedPin5 = newportState & 11101111
print clearedPin5
>>> 0b011*0*0000

If these binary operations are foreign, I recommend this excellent tutorial over on avrfreaks. I would become intimate with them before progressing further. Embedded software concepts like these are full of bitmasks and bitshifting.

Answer 2

I've made this function to control the pins individually (code derived from here and here):

def setPin(pin,value):
    if(pin==1):
        p.setDataStrobe(value)
    elif(pin>=2 and pin<=9):
        pin = pin-2
        if(value==0):
            # clear the bit
            p.setData(p.getData() & (255 - pow(2, pin)))
        else:
            #set the bit
            p.setData(p.getData() | pow(2, pin))
    elif(pin==14):
        p.setAutoFeed(value)
    elif(pin==16):
        p.setInitOut(value)
    elif(pin==17):
        p.setSelect(value)
    else:
        raise(ValueError("invalid pin number"))