I'm new to R. My data has 600k objects defined by three attributes: Id
, Date
and TimeOfCall
.
TimeofCall
has a 00:00:00
format and range from 00:00:00
to 23:59:59
.
I want to bin the TimeOfCall
attribute, into 24 bins, each one representing hourly slot (first bin 00:00:00
to 00:59:59
and so on).
Can someone talk me through how to do this? I tried using cut()
but apparently my format is not numeric. Thanks in advance!
While you could convert to a formal time representation, in this case it might be easier to just use substr
:
test <- c("00:00:01","02:07:01","22:30:15")
as.numeric(substr(test,1,2))
#[1] 0 2 22
Using a POSIXct
time to deal with it would also work, and might be handy if you plan on further calculations (differences in time etc):
testtime <- as.POSIXct(test,format="%H:%M:%S")
#[1]"2013-12-09 00:00:01 EST" "2013-12-09 02:07:01 EST" "2013-12-09 22:30:15 EST"
as.numeric(format(testtime,"%H"))
#[1] 0 2 22
You can use cut.POsixlt
function. But you should coerce your data to a valid time object. here I am using handy hms
from lubridate
. And strftime
to get the time format.
library(lubridate)
x <- c("09:10:01", "08:10:02", "08:20:02","06:10:03 ", "Collided at 9:20:04 pm")
x.h <- strftime(cut(as.POSIXct(hms(x),origin=Sys.Date()),'hours'),
format='%H:%M:%S')
data.frame(x,x.h)
x x.h
1 09:10:01 10:00:00
2 08:10:02 09:00:00
3 08:20:02 09:00:00
4 06:10:03 07:00:00
5 Collided at 9:20:04 pm 22:00:00
来源:https://stackoverflow.com/questions/20461043/binning-time-series-in-r