read stdin in function in bash script

问题

I have some set of bash functions which output some information:

find-modelname-in-epson-ppds
find-modelname-in-samsung-ppds
find-modelname-in-hp-ppds
etc ...

I've been writing functions which read output and filter it:

function filter-epson {
    find-modelname-in-epson-ppds | sed <bla-blah-blah>
}

function filter-hp {
    find-modelname-in-hp-ppds | sed <the same bla-blah-blah>
}
etc ...

But the I thought that it would be better do something like this:

function filter-general {
    (somehow get input) | sed <bla-blah-blah>
}

and then call in another high-level functions:

function high-level-func {
    # outputs filtered information
    find-modelname-in-hp/epson/...-ppds | filter-general 
}

How can I achieve that with the best bash practices?

回答1:

If the question is How do I pass stdin to a bash function?, then the answer is:

Shellscript functions take stdin the ordinary way, as if they were commands or programs. :)

input.txt:

HELLO WORLD
HELLO BOB
NO MATCH

test.sh:

#!/bin/sh

myfunction() {
    grep HELLO
}

cat input.txt | myfunction

Output:

hobbes@metalbaby:~/scratch$ ./test.sh 
 HELLO WORLD 
 HELLO BOB

Note that command line arguments are ALSO handled in the ordinary way, like this:

test2.sh:

#!/bin/sh

myfunction() {
    grep "$1"
}

cat input.txt | myfunction BOB

Output:

hobbes@metalbaby:~/scratch/$ ./test2.sh 
 HELLO BOB

回答2:

To be painfully explicit that I'm piping from stdin, I sometimes write

cat - | ...

回答3:

Call sed directly. That's it.

function filter-general {
    sed <bla-blah-blah>
}

回答4:

A very simple means to get stdin into a variable is to use read. By default, it reads file descriptor "0", i.e. stdin i.e., /dev/stdin.

Example Function:

input(){ local in; read in; echo you said $in; }

Example implementation:

echo "Hello World" | input

Result:

you said Hello World

Additional info

You don't need to declare a variable as being local, of course. I just included that for the sake of good form. Plain old read in does what you need.

So you understand how read works, by default it reads data off the given file descriptor (or implicit stdin) and blocks until it encounters a newline. Much of the time, you'll find that will implicitly be attached to your input, even if you weren't aware of it. If you have a function that seems to "hang", with this mechanism just keep this detail in mind (there are other ways of using read to deal with that).

More robust solutions

Adding on the prior example, here's a variation that lets you pass the input via a stdin OR an argument:

input()
{ 
    local in=$1 if [ -z "$in" ]; then read in; fi
    echo you said $in
}

With that tweak, you could ALSO call the function like:

input "Hello World"

How about handling an stdin option plus other multiple arguments? Many standard nix utilities, especially those which typically work with stdin/stdout adhere to the common practice of treating a dash - to mean "default", which contextually means either stdin or stdout, so you can follow the convention, and treat an argument specified as - to mean "stdin":

input()
{ 
    local a=$1; if [ "$a" == "-" ]; then read a; fi
    local b=$2
    echo you said $a $b
}

Call this like:

input "Hello" "World"

echo "Hello" | input - "World"

Going even further, there is actually no reason to only limit stdin to being an option for only the first argument! You might create a super flexible function that could use it for any of them...

input()
{ 
    local a=$1; if [ "$a" == "-" ]; then read a; fi
    local b=$2; if [ "$b" == "-" ]; then read b; fi
    echo you said $a $b
}

Why would you what that? Because you could formulate and pipe in whatever argument you might need...

myFunc | input "Hello" -

In this case, I pipe in the 2nd argument using the results of myFunc rather than the only having the option for the first.

来源：https://stackoverflow.com/questions/14004756/read-stdin-in-function-in-bash-script

标签

bash

shell

pipe

bash-function