问题
I just got some C code that uses extern "C" to declare external functions like this:
extern "C" void func();
Is this valid C? I'm getting an error at this line, but I'm not sure if it's because of this or something else.
回答1:
No, it's not valid C. It should only be used in C++ code to refer to functions defined in C code. The extern "C"
should be surrounded in a ifdef __cplusplus
/#endif
block:
// For one function
#ifdef __cplusplus
extern "C"
#endif
void func();
// For more than one function
#ifdef __cplusplus
extern "C"
{
#endif
void func1();
void func2();
#ifdef __cplusplus
}
#endif
回答2:
this is a C++ notation to tell the compiler/linker to use C calling standards.
Usually that line is wrapped in an pre-processor statement.
#ifdef __cplusplus
extern "C" {
#endif
// stuff
#ifdef __cplusplus
}
#endif
回答3:
Not valid in C. If present after preprocessing this will result in a diagnostic as per the standard.
For C++, this turns of name-mangling. See this for more details as to why it may be required. Can you post some more details?
来源:https://stackoverflow.com/questions/717729/does-extern-c-have-any-effect-in-c