问题
Ok this has been become sooo confusing to me. I just don't know what is wrong with this assignment:
void *pa; void *pb;
char *ptemp; char *ptemp2;
ptemp = (char *)pa;
ptemp2 = (char *)pb;
Can anyone tell me why I'm getting this error:
error: invalid conversion from ‘void*’ to ‘char*’
回答1:
Actually, there must be something wrong with your compiler(or you haven't told the full story). It is perfectly legal to cast a void*
to char*
. Furthermore, the conversion is implicit in C (unlike C++), that is, the following should compile as well
char* pChar;
void* pVoid;
pChar = (char*)pVoid; //OK in both C and C++
pChar = pVoid; //OK in C, convertion is implicit
回答2:
I just tried your code in a module called temp.c. I added a function called f1.
void *pa; void *pb;
char *ptemp; char *ptemp2;
f1()
{
ptemp = (char *)pa;
ptemp2 = (char *)pb;
}
On Linux I entered gcc -c temp.c, and this compiled with no errors or warnings.
On which OS are you trying this?
来源:https://stackoverflow.com/questions/7067927/how-do-you-convert-void-pointer-to-char-pointer-in-c