问题
I have a program that requires much memory, like 2/3 of all the physical ram. After some runtime my operating system begins to swap the program to hdd. But I need the program to respond very fast all the time, so I need to prevent paging for that process.
How can you prevent the OS to swap one process?
Thanks for any help!
回答1:
At the start of the program, call:
mlockall(MCL_CURRENT | MCL_FUTURE);
(If you do not have the source to the program, you'll have to debauch the process with ptrace to do this).
Be aware that this will increase the chances of memory allocations made by the process failing.
回答2:
Well, there's mlock for locking memory (telling the kernel it may not be swapped out), but that's meant for relatively small amounts of memory, and would require modification of the program.
The other option might be to adjust Linux's "swappiness", i.e. its tendency to swap out pages. See here for an interesting discussion. That is not possible per process, however.
I'm not aware of any per-process solution for your problem.
回答3:
Use mmap() instead of malloc, and use the "MAP_LOCKED" flag. (works on linux > 2.5.37)
来源：https://stackoverflow.com/questions/2360116/how-to-prevent-paging-for-one-program-process