jquery find next element with class

若如初见. 提交于 2019-12-04 14:59:30

问题


I'm trying to find the next element with a class of "error" and hitting a wall.

In looking at the demo on jQuery's site, this should work, but doesn't.

$("button[disabled]").next().text("this button is disabled");

<div>
   <button disabled="disabled">First</button>
   <span>no overwrite</span>
   <span class="error"></span>
</div>

<div>
   <button>Second</button>
   <span></span>
</div>

<div>
   <button disabled="disabled">Third</button>
   <span>no overwrite</span>
   <span class="error"></span>
</div>

I'm trying to find the span or div or whatever after the element in question, like the button above.

so the disabled button line should read, 'no overwrite this button is diabled'

I've tried

$("button[disabled]").next(".error").text("this button is disabled");

to no avail.


回答1:


The problem is that your using the next traversing function rather than nextAll

$("button[disabled]").nextAll(".error").text("this button is disabled");

When you use next its just looking at the "next" element which is

<span>no overwrite</span>

Next all looks at all siblings that are next




回答2:


Try this:

$("button[disabled=disabled]").parent().find("span.error").text("this button is disabled");

hope it helps. Sinan.




回答3:


next() won't work in this case because it has to be a sibling for that to work. In this case you need:

$("button[disabled]").parent().nextAll()
  .find("span.error:first").text("this button is disabled");


来源:https://stackoverflow.com/questions/1793944/jquery-find-next-element-with-class

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