问题
Recently I came across one interesting question on linked list. Sorted singly linked list is given and we have to search one element from this list.
Time complexity should not be more than O(log n). This seems that we need to apply binary search on this linked list. How? As linked list does not provide random access if we try to apply binary search algorithm it will reach O(n) as we need to find length of the list and go to the middle.
Any ideas?
回答1:
It is certainly not possible with a plain singly-linked list.
Sketch proof: to examine the last node of a singly-linked list, we must perform n-1 operations of following a "next" pointer [proof by induction on the fact that there is only one reference to the k+1th node, and it is in the kth node, and it takes a operation to follow it]. For certain inputs, it is necessary to examine the last node (specifically, if the searched-for element is equal to or greater than its value). Hence for certain inputs, time required is proportional to n.
You either need more time, or a different data structure.
Note that you can do it in O(log n) comparisons with a binary search. It'll just take more time than that, so this fact is only of interest if comparisons are very much more expensive than list traversal.
回答2:
You need to use skip list. This is not possible with a normal linked list (and I really want to learn if this is possible with normal list).
回答3:
In Linked List, binary search may not achieve a complexity of O(log n) but least can be achieved a little by using Double Pointer Method as described here in this research work: http://www.ijcsit.com/docs/Volume%205/vol5issue02/ijcsit20140502215.pdf
回答4:
As noted, this is not in general possible. However, in a language like C, if the list nodes are contiguously allocated, it would be possible to treat the structure as an array of nodes.
Obviously, this is only an answer to a trick question variant of this problem, but the problem is always an impossibility or a trick question.
回答5:
Yes, it is possible in java language as below..
Collections.<T>binarySearch(List<T> list, T key)
for binary search on any List. It works on ArrayList and on LinkedList and on any other List.
回答6:
Use MAPS to create LINK LISTS.
Map M , M[first element]=second element , M[second element]=third element ,
...
...
its a linked list...
but because its a map...
which internally uses binary search to search any element..
any searching of elements will take O(log n)
来源：https://stackoverflow.com/questions/5281053/how-to-apply-binary-search-olog-n-on-a-sorted-linked-list