Passing a structure through Sockets in C

问题

I am trying to pass whole structure from client to server or vice-versa. Let us assume my structure as follows

struct temp {
  int a;
  char b;
}

I am using sendto and sending the address of the structure variable and receiving it on the other side using the recvfrom function. But I am not able to get the original data sent on the receiving end. In sendto function I am saving the received data into variable of type struct temp.

n = sendto(sock, &pkt, sizeof(struct temp), 0, &server, length);
n = recvfrom(sock, &pkt, sizeof(struct temp), 0, (struct sockaddr *)&from,&fromlen);

Where pkt is the variable of type struct temp.

Eventhough I am receiving 8bytes of data but if I try to print it is simply showing garbage values. Any help for a fix on it ?

NOTE: No third party Libraries have to be used.

EDIT1: I am really new to this serialization concept .. But without doing serialization cant I send a structure via sockets ?

EDIT2: When I try to send a string or an integer variable using the sendto and recvfrom functions I am receiving the data properly at receiver end. Why not in the case of a structure? If I don\'t have to use serializing function then should I send each and every member of the structure individually? This really is not a suitable solution since if there are \'n\' number of members then there are \'n\' number of lines of code added just to send or receive data.

回答1:

This is a very bad idea. Binary data should always be sent in a way that:

Handles different endianness
Handles different padding
Handles differences in the byte-sizes of intrinsic types

Don't ever write a whole struct in a binary way, not to a file, not to a socket.

Always write each field separately, and read them the same way.

You need to have functions like

unsigned char * serialize_int(unsigned char *buffer, int value)
{
  /* Write big-endian int value into buffer; assumes 32-bit int and 8-bit char. */
  buffer[0] = value >> 24;
  buffer[1] = value >> 16;
  buffer[2] = value >> 8;
  buffer[3] = value;
  return buffer + 4;
}

unsigned char * serialize_char(unsigned char *buffer, char value)
{
  buffer[0] = value;
  return buffer + 1;
}

unsigned char * serialize_temp(unsigned char *buffer, struct temp *value)
{
  buffer = serialize_int(buffer, value->a);
  buffer = serialize_char(buffer, value->b);
  return buffer;
}

unsigned char * deserialize_int(unsigned char *buffer, int *value);

Or the equivalent, there are of course several ways to set this up with regards to buffer management and so on. Then you need to do the higher-level functions that serialize/deserialize entire structs.

This assumes serializing is done to/from buffers, which means the serialization doesn't need to know if the final destination is a file or a socket. It also means you pay some memory overhead, but it's generally a good design for performance reasons (you don't want to do a write() of each value to the socket).

Once you have the above, here's how you could serialize and transmit a structure instance:

int send_temp(int socket, const struct sockaddr *dest, socklen_t dlen,
              const struct temp *temp)
{
  unsigned char buffer[32], *ptr;

  ptr = serialize_temp(buffer, temp);
  return sendto(socket, buffer, ptr - buffer, 0, dest, dlen) == ptr - buffer;
}

A few points to note about the above:

The struct to send is first serialized, field by field, into buffer.
The serialization routine returns a pointer to the next free byte in the buffer, which we use to compute how many bytes it serialized to
Obviously my example serialization routines don't protect against buffer overflow.
Return value is 1 if the sendto() call succeeded, else it will be 0.

回答2:

Using the 'pragma' pack option did solved my problem but I am not sure if it has any dependencies ??

#pragma pack(1)   // this helps to pack the struct to 5-bytes
struct packet {
int i;
char j;
};
#pragma pack(0)   // turn packing off

Then the following lines of code worked out fine without any problem

n = sendto(sock,&pkt,sizeof(struct packet),0,&server,length);

n = recvfrom(sock, &pkt, sizeof(struct packet), 0, (struct sockaddr *)&from, &fromlen);

回答3:

There is no need to write own serialisation routines for short and long integer types - use htons()/htonl() POSIX functions.

回答4:

If you don't want to write the serialisation code yourself, find a proper serialisation framework, and use that.

Maybe Google's protocol buffers would be possible?

回答5:

Serialization is a good idea. You can also use Wireshark to monitor the traffic and understand what is actually passed in the packets.

回答6:

Instead of serialising and depending on 3rd party libraries its easy to come up with a primitive protocol using tag, length and value.

Tag: 32 bit value identifying the field
Length: 32 bit value specifying the length in bytes of the field
Value: the field

Concatenate as required. Use enums for the tags. And use network byte order...

Easy to encode, easy to decode.

Also if you use TCP remember it is a stream of data so if you send e.g. 3 packets you will not necessarily receive 3 packets. They maybe be "merged" into a stream depending on nodelay/nagel algorithm amongst other things and you may get them all in one recv... You need to delimit the data for example using RFC1006.

UDP is easier, you'll receive a distinct packet for each packet sent, but its a lot less secure.

回答7:

If the format of the data you want to transfer is very simple then converting to and from an ANSI string is simple and portable.

来源：https://stackoverflow.com/questions/1577161/passing-a-structure-through-sockets-in-c

标签

sockets

recv

sendto