问题
I have read quite some posts that say compare and swap guarantees atomicity, However I am still not able to get how does it. Here is general pseudo code for compare and swap:
int CAS(int *ptr,int oldvalue,int newvalue)
{
int temp = *ptr;
if(*ptr == oldvalue)
*ptr = newvalue
return temp;
}
How does this guarantee atomicity? For example, if I am using this to implement a mutex,
void lock(int *mutex)
{
while(!CAS(mutex, 0 , 1));
}
how does this prevent 2 threads from acquiring the mutex at the same time? Any pointers would be really appreciated.
回答1:
"general pseudo code" is not an actual code of CAS (compare and swap) implementation. Special hardware instructions are used to activate special atomic hardware in the CPU. For example, in x86 the LOCK CMPXCHG
can be used (http://en.wikipedia.org/wiki/Compare-and-swap).
In gcc, for example, there is __sync_val_compare_and_swap()
builtin - which implements hardware-specific atomic CAS. There is description of this operation from fresh wonderful book from Paul E. McKenney (Is Parallel Programming Hard, And, If So, What Can You Do About It?, 2014), section 4.3 "Atomic operations", pages 31-32.
If you want to know more about building higher level synchronization on top of atomic operations and save your system from spinlocks and burning cpu cycles on active spinning, you can read something about futex
mechanism in Linux. First paper on futexes is Futexes are tricky by Ulrich Drepper 2011; the other is LWN article http://lwn.net/Articles/360699/ (and the historic one is Fuss, Futexes and Furwocks: Fast Userland Locking in Linux, 2002)
Mutex locks described by Ulrich use only atomic operations for "fast path" (when the mutex is not locked and our thread is the only who wants to lock it), but if the mutex was locked, the thread will go to sleeping using futex(FUTEX_WAIT...) (and it will mark the mutex variable using atomic operation, to inform the unlocking thread about "there are somebody sleeping waiting on this mutex", so unlocker will know that he must wake them using futex(FUTEX_WAKE, ...)
回答2:
How does it prevent two threads from acquiring the lock? Well, once any one thread succeeds, *mutex
will be 1
, so any other thread's CAS will fail (because it's called with expected value 0
). The lock is released by storing 0
in *mutex
.
Note that this is an odd use of CAS, since it's essentially requiring an ABA-violation. Typically you'd just use a plain atomic exchange:
while (exchange(mutex, 1) == 1) { /* spin */ }
// critical section
*mutex = 0; // atomically
Or if you want to be slightly more sophisticated and store information about which thread has the lock, you can do tricks with atomic-fetch-and-add (see for example the Linux kernel spinlock code).
来源:https://stackoverflow.com/questions/22339466/how-compare-and-swap-works