Why would anyone want to overload the & (address-of) operator? [duplicate]

别来无恙 提交于 2019-12-04 10:01:45

问题


Possible Duplicate:
What legitimate reasons exist to overload the unary operator& ?

I just read this question, and I can't help but wonder:

Why would anyone possibly want to overload the & ("address-of") operator?

   some_class* operator&() const { return address_of_object; }

Is there any legitimate use case?


回答1:


If you're dealing with any sort of wrapper objects, you might want or need to transparently forward the access to the wrapper to the contained object. In that case, you can't return a pointer to the wrapper, but need to overload the address-of operator to return a pointer to the contained object.




回答2:


Because they're evil and want you to suffer.

Or I guess if you are using proxy objects? I suppose you might want to return a pointer to the managed object instead of the container - although i'd rather do that with a getter function. Otherwise you'd have to remember to use things like boost::addressof.




回答3:


Yes, for debugging (if you want to trace any access or reference, you might want to put a log line on any call to &, * or ->).




回答4:


I have seen this in productive code already.

But there, a binary representation of the content of a struct was returned, not just 0.

And the usecase was simple: Binary operations.



来源:https://stackoverflow.com/questions/6499502/why-would-anyone-want-to-overload-the-address-of-operator

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