Android Webview with Back Button, if else

问题

Disregard. I was opening the wrong app that was installed. It works wonderfully. :)

I have the back button working correctly within my webview, but I was wondering something. How to make the webview go back until it cannot anymore, and instead of exiting the program, have it open up a dialog box asking if the user is sure they won't to exit. Here is my take on the code.
Thanks for taking the time.

.java file

package com.vtd.whatthe;

import android.app.Activity;
import android.app.AlertDialog;
import android.app.AlertDialog.Builder;
import android.app.Dialog;
import android.content.DialogInterface;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
import android.widget.Toast;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class WhatThe extends Activity {
    private WebView webview;

    /** Called when the activity is first created. */

    public void onBackPressed (){

        if (webview.isFocused() && webview.canGoBack()) {
                webview.goBack();       
        }
        else {
                openMyDialog(null);

        }
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        webview = (WebView) findViewById(R.id.webview);
        webview.setWebViewClient(new HelloWebViewClient());
        webview.getSettings().setJavaScriptEnabled(true);
        webview.setInitialScale(50); 
        webview.getSettings().setUseWideViewPort(true); 
        webview.loadUrl("http://test2.com/");
    }
    private class HelloWebViewClient extends WebViewClient {

        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            view.loadUrl(url);
            return true;
        }

            }

    public void openMyDialog(View view) {
        showDialog(10);
    }

    @Override
    protected Dialog onCreateDialog(int id) {
        switch (id) {
        case 10:
            // Create our AlertDialog
            Builder builder = new AlertDialog.Builder(this);
            builder.setMessage("Are you sure you want to exit? You have unlimited guesses!")
                    .setCancelable(true)
                    .setPositiveButton("Yes",
                            new DialogInterface.OnClickListener() {
                                @Override
                                public void onClick(DialogInterface dialog,
                                        int which) {
                                    // Ends the activity
                                    WhatThe.this.finish();
                                }
                            })
                    .setNegativeButton("Keep Guessing!",
                            new DialogInterface.OnClickListener() {

                                @Override
                                public void onClick(DialogInterface dialog,
                                        int which) {
                                    Toast.makeText(getApplicationContext(),
                                            "Good Luck!",
                                            Toast.LENGTH_SHORT).show();
                                }
                            });

            return builder.create();


        }
        return super.onCreateDialog(id);
    }
}

回答1:

The below code worked for me

public void onBackPressed (){

    if (webview.isFocused() && webview.canGoBack()) {
            webview.goBack();       
    }
    else {
            super.onBackPressed();
            finish();
    }
}

回答2:

Try this

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) 
{
    if(event.getAction() == KeyEvent.ACTION_DOWN)
    {
        switch(keyCode)
        {
        case KeyEvent.KEYCODE_BACK:
            if(webView.canGoBack())
            {
                myWebView.goBack();
            }
            else
            {
                finish();
            }
            return true;
        }
    }
    return super.onKeyDown(keyCode, event);
}

回答3:

try the following snippet

public void back() {
    if (history.size() > 0) {
        history.remove(history.size() - 1);
        if (history.size() <= 0) {
            finish();
        } else {
            setContentView(history.get(history.size() - 1));
        }
    } else {
        finish();
    }
}

@Override
public void onBackPressed() {
    TopNewsGroup.group.back();
}

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_BACK) {
        TopNewsGroup.group.back();
        return true;
    }
    return super.onKeyDown(keyCode, event);
}

回答4:

This is the code that you need.

public void showAlertDialog(Context context, String title, String message, Boolean status) {
    AlertDialog.Builder adb = new AlertDialog.Builder(this);
    adb.setTitle(R.string.alerta);
    adb.setMessage(getResources().getString(R.string.mserror));
    adb.setIcon((status) ? R.drawable.close : R.drawable.alerta);

    adb.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() {
       public void onClick(DialogInterface dialog, int which) {
        finish();
    } });

    adb.setNegativeButton(R.string.cancel, new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int which) {
        } });

    adb.show();
}

And then

public void onBackPressed(){

    if (webView.isFocused() && webView.canGoBack()) {
        webView.goBack();       
    }
    else {
        showAlertDialog(Web.this, "","", false);
    }
}

来源：https://stackoverflow.com/questions/6220602/android-webview-with-back-button-if-else