Say, I have a dic like this
my_dictionary = {'a':1,'c':5,'b':20,'d':7}
Now, I want to do this with my dic:
if my_dictionary['a'] == 1 and my_dictionary['d'] == 7:
print my_dictionary['c']
This looks ridiculous because I am typing my_dictionary 3 times!
So is there any syntax which would allow me to do something like this:
within my_dictionary:
if a == 1 and d == 7:
print c
This would actually work if I didn't have anything more (in this case b) in my dic:
def f(a,d,c):
if a == 1 and d == 7:
print c
f(**my_dictionary)
You can change your function to
def f(a,d,c,**args):
if a == 1 and d == 7:
print c
then it will work even if you have other items in the dict.
You can use operator.itemgetter
to minimize multiple indexing :
>>> if operator.itemgetter('a','d')(my_dictionary)==(1,7):
... print operator.itemgetter('c')(my_dictionary)
And you can use it in a function :
>>> def get_item(*args):
... return operator.itemgetter(*args)(my_dictionary)
...
>>>
>>> if get_item('a','d')==(1,7):
... print get_item('c')
...
5
To answer
So is there any syntax which would allow me to do something like this:
within my_dictionary: if a == 1 and d == 7: print c
You can subclass dict so that it has with
magic methods. To do this, the class must have __enter__
and __exit__
methods. You could then export the keys to the local scope of the with statement and clean them up with the exit method.
Using this answer I was able to create a subclass that did so:
import inspect
import ctypes
locals_to_fast = ctypes.pythonapi.PyFrame_LocalsToFast
locals_to_fast.restype = None
locals_to_fast.argtypes = [ctypes.py_object, ctypes.c_int]
class WithDict(dict):
def __enter__(self):
frame = self.get_frame()
for k,v in self.iteritems():
frame.f_locals[str(k)] = v
locals_to_fast(frame, 1)
def __exit__(self, exc_type, exc_value, traceback):
frame = self.get_frame()
for k in self.keys():
del frame.f_locals[str(k)]
def get_frame(self):
return inspect.getouterframes(inspect.currentframe())[2][0]
A test case using your original example
my_dictionary = WithDict({'a':1,'c':5,'b':20,'d':7})
with my_dictionary:
if a == 1 and d == 7:
print c
prints 5
The variables get deleted when the with
statement completes
来源:https://stackoverflow.com/questions/31675756/temporarily-unpack-dictionary