parse query string with urllib in Python 2.4

问题

Using Python2.4.5 (don't ask!) I want to parse a query string and get a dict in return. Do I have to do it "manually" like follows?

>>> qs = 'first=1&second=4&third=3'
>>> d = dict([x.split("=") for x in qs.split("&")])
>>> d
{'second': '4', 'third': '3', 'first': '1'}

Didn't find any useful method in urlparse.

回答1:

You have two options:

>>> cgi.parse_qs(qs)
{'second': ['4'], 'third': ['3'], 'first': ['1']}

or

>>> cgi.parse_qsl(qs)
[('first', '1'), ('second', '4'), ('third', '3')]

The values in the dict returned by cgi.parse_qs() are lists rather than strings, in order to handle the case when the same parameter is specified several times:

>>> qs = 'tags=python&tags=programming'
>>> cgi.parse_qs(qs)
{'tags': ['python', 'programming']}

回答2:

this solves the annoyance:

d = dict(urlparse.parse_qsl( qs ) )

personally i would expect there two be a built in wrapper in urlparse. in most cases i wouldn't mind to discards the redundant parameter if such exist

回答3:

import urlparse
qs = 'first=1&second=4&third=3&first=0'

print dict(urlparse.parse_qsl(qs))

OR

print urlparse.parse_qs(qs)

来源：https://stackoverflow.com/questions/1769625/parse-query-string-with-urllib-in-python-2-4