Django MTMField: limit_choices_to = other_ForeignKeyField_on_same_model?

喜夏-厌秋 提交于 2019-12-04 08:53:14

I would delete site field on my Photo model and add a ForeignKey to Gallery. I would remove limit_choices_to from photos fields on Gallery model.

Because you are using ForeignKeys to Sites, that means sites don't share galleries and photos. Therefore having those I mentioned above is already useless.

class Photo(models.Model):
    title = models.CharField(max_length=100)
    gallery = models.ForeignKey(Gallery, related_name='photos')
    file = models.ImageField(upload_to=get_site_profile_path) 

    def __unicode__(self):
        return self.title


class Gallery(models.Model):    
    name = models.CharField(max_length=40)
    site = models.ForeignKey(Site)

    def __unicode__(self):
        return self.name

Once you set the site on a gallery all its photos will inherit this property. And the site will be accessible as photo_instance.gallery.site:

@property
def site(self):
    return self.gallery.site

This should work as if you had a site field. But I haven't tested it.

Things change or course, if you decide that a gallery or a photo can appear in multiple sites.

Yes. You need to override the form that admin uses for the Gallery model, then limit the queryset of the photos field in that form:

class GalleryAdminForm(django.forms.ModelForm):

    class Meta:
        model = Gallery

    def __init__(self, *args, **kwargs):
        super(GalleryAdminForm, self).__init__(*args, **kwargs)
        self.fields['segments'].queryset = Photo.objects.filter(site=self.instance.site)


class GalleryAdmin(django.contrib.admin.ModelAdmin):
    form = GalleryAdminForm

django.contrib.admin.site.register(Gallery, GalleryAdmin)
Tom

According to the docs, "limit_choices_to has no effect when used on a ManyToManyField with an intermediate table". By my reading, that means it has no effect at all, because ManyToManyFields use intermediate tables...

I haven't tried to make it work in the Admin site, but from your own views, you can create a form and override the queryset used to populate the list of choices:

form.fields["photos"].queryset = request.user.photo_set.all()
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