Can FFmpeg be used as a library, instead of a standalone program?

Question

I'd like to add video conversion capabilities to a program I'm writing. FFmpeg's command line interface for doing this is simply ffmpeg -i InputFile OutputFile, but is there a way to make use of it as a library, so I can do something like ffmpeg_convert(InputFile, OutputFile)?

I'm hoping I won't have to use libavcodec directly, as I imagine it will be far more complex than a one-line function to convert between formats. If FFmpeg can't be easily retrofitted to do this, is there perhaps another library based on it that does? I've heard of libvlc, but that seems to only expose a video playing API, not video conversion.

Thanks.

Answer 1

You need libavcodec and libavformat. The FAQ tells you:

4.1 Are there examples illustrating how to use the FFmpeg libraries, particularly libavcodec and libavformat?

Yes. Read the Developers Guide of the FFmpeg documentation. Alternatively, examine the source code for one of the many open source projects that already incorporate FFmpeg at (projects.html).

The FFmpeg documentation guide can be found at ffmpeg.org/documentation.html, including the Developer's guide. I suggest looking at libavformat/output-example.c or perhaps the source of the ffmpeg command line utility itself.

Answer 2

If you just wanted to make a call to ffmpeg as function rather than a system call, you can do that pretty easily.

in ffmpeg.c, change:

int main(int argc, char **argv) to int ffmpeg((int argc, char **argv)

Then in your call the ffmpeg function and pass in an array that mimics the command line. To make it even easier use a function to create the argc, argv variables.

static int setargs(char *args, char **argv)
{
    int count = 0;

    while (isspace(*args)) ++args;
    while (*args) {
        if (argv) argv[count] = args;
        while (*args && !isspace(*args)) ++args;
        if (argv && *args) *args++ = '\0';
        while (isspace(*args)) ++args;
        count++;
    }
}

char **parsedargs(char *args, int *argc)
{
    char **argv = NULL;
    int    argn = 0;

    if (args && *args
        && (args = strdup(args))
        && (argn = setargs(args,NULL))
        && (argv = malloc((argn+1) * sizeof(char *)))) {
          *argv++ = args;
          argn = setargs(args,argv);
    }

    if (args && !argv) free(args);

    *argc = argn;
    return argv;
}

void freeparsedargs(char **argv)
{
    if (argv) {
        free(argv[-1]);
        free(argv-1);
    }
}
    return count;
}

int main()
{
    char **argv;
    char *cmd;
    int argc;

    cmd = "ffmpeg -i infile outfile";
    argv = parsedargs(cmd,&argc);
    ffmpeg(argc, argv);
}

Answer 3

Yes you have to use libavcodec and libavformat. I think you should read about ffplay.c inside ffmpeg source code. I think it would be easier for you to start with that file.