问题
The oodocx module mentioned in the same page refers the user to an /examples folder that does not seem to be there.
I have read the documentation of python-docx 0.7.2, plus everything I could find in Stackoverflow on the subject, so please believe that I have done my “homework”.
Python is the only language I know (beginner+, maybe intermediate), so please do not assume any knowledge of C, Unix, xml, etc.
Task : Open a ms-word 2007+ document with a single line of text in it (to keep things simple) and replace any “key” word in Dictionary that occurs in that line of text with its dictionary value. Then close the document keeping everything else the same.
Line of text (for example) “We shall linger in the chambers of the sea.”
from docx import Document
document = Document('/Users/umityalcin/Desktop/Test.docx')
Dictionary = {‘sea’: “ocean”}
sections = document.sections
for section in sections:
print(section.start_type)
#Now, I would like to navigate, focus on, get to, whatever to the section that has my
#single line of text and execute a find/replace using the dictionary above.
#then save the document in the usual way.
document.save('/Users/umityalcin/Desktop/Test.docx')
I am not seeing anything in the documentation that allows me to do this—maybe it is there but I don’t get it because everything is not spelled-out at my level.
I have followed other suggestions on this site and have tried to use earlier versions of the module (https://github.com/mikemaccana/python-docx) that is supposed to have "methods like replace, advReplace" as follows: I open the source-code in the python interpreter, and add the following at the end (this is to avoid clashes with the already installed version 0.7.2):
document = opendocx('/Users/umityalcin/Desktop/Test.docx')
words = document.xpath('//w:r', namespaces=document.nsmap)
for word in words:
if word in Dictionary.keys():
print "found it", Dictionary[word]
document = replace(document, word, Dictionary[word])
savedocx(document, coreprops, appprops, contenttypes, websettings,
wordrelationships, output, imagefiledict=None)
Running this produces the following error message:
NameError: name 'coreprops' is not defined
Maybe I am trying to do something that cannot be done—but I would appreciate your help if I am missing something simple.
If this matters, I am using the 64 bit version of Enthought's Canopy on OSX 10.9.3
回答1:
The current version of python-docx does not have a search() function or a replace() function. These are requested fairly frequently, but an implementation for the general case is quite tricky and it hasn't risen to the top of the backlog yet.
Several folks have had success though, getting done what they need, using the facilities already present. Here's an example. It has nothing to do with sections by the way :)
for paragraph in document.paragraphs:
if 'sea' in paragraph.text:
print paragraph.text
paragraph.text = 'new text containing ocean'
To search in Tables as well, you would need to use something like:
for table in document.tables:
for cell in table.cells:
for paragraph in cell.paragraphs:
if 'sea' in paragraph.text:
...
If you pursue this path, you'll probably discover pretty quickly what the complexities are. If you replace the entire text of a paragraph, that will remove any character-level formatting, like a word or phrase in bold or italic.
By the way, the code from @wnnmaw's answer is for the legacy version of python-docx and won't work at all with versions after 0.3.0.
回答2:
I needed something to replace regular expressions in docx. I took scannys answer. To handle style I've used answer from: Python docx Replace string in paragraph while keeping style added recursive call to handle nested tables. and came up with something like this:
import re
from docx import Document
def docx_replace_regex(doc_obj, regex , replace):
for p in doc_obj.paragraphs:
if regex.search(p.text):
inline = p.runs
# Loop added to work with runs (strings with same style)
for i in range(len(inline)):
if regex.search(inline[i].text):
text = regex.sub(replace, inline[i].text)
inline[i].text = text
for table in doc_obj.tables:
for row in table.rows:
for cell in row.cells:
docx_replace_regex(cell, regex , replace)
regex1 = re.compile(r"your regex")
replace1 = r"your replace string"
filename = "test.docx"
doc = Document(filename)
docx_replace_regex(doc, regex1 , replace1)
doc.save('result1.docx')
To iterate over dictionary:
for word, replacement in dictionary.items():
word_re=re.compile(word)
docx_replace_regex(doc, word_re , replacement)
Note that this solution will replace regex only if whole regex has same style in document.
Also if text is edited after saving same style text might be in separate runs. For example if you open document that has "testabcd" string and you change it to "test1abcd" and save, even dough its the same style there are 3 separate runs "test", "1", and "abcd", in this case replacement of test1 won't work.
This is for tracking changes in the document. To marge it to one run, in Word you need to go to "Options", "Trust Center" and in "Privacy Options" unthick "Store random numbers to improve combine accuracy" and save the document.
回答3:
The Office Dev Centre has an entry in which a developer has published (MIT licenced at this time) a description of a couple of algorithms that appear to suggest a solution for this (albeit in C#, and require porting):" MS Dev Centre posting
回答4:
The problem with your second attempt is that you haven't defined the parameters that savedocx needs. You need to do something like this before you save:
relationships = docx.relationshiplist()
title = "Document Title"
subject = "Document Subject"
creator = "Document Creator"
keywords = []
coreprops = docx.coreproperties(title=title, subject=subject, creator=creator,
keywords=keywords)
app = docx.appproperties()
content = docx.contenttypes()
web = docx.websettings()
word = docx.wordrelationships(relationships)
output = r"path\to\where\you\want\to\save"
回答5:
he changed the API in docx py again...
for the sanity of everyone coming here:
import datetime
import os
from decimal import Decimal
from typing import NamedTuple
from docx import Document
from docx.document import Document as nDocument
class DocxInvoiceArg(NamedTuple):
invoice_to: str
date_from: str
date_to: str
project_name: str
quantity: float
hourly: int
currency: str
bank_details: str
class DocxService():
tokens = [
'@INVOICE_TO@',
'@IDATE_FROM@',
'@IDATE_TO@',
'@INVOICE_NR@',
'@PROJECTNAME@',
'@QUANTITY@',
'@HOURLY@',
'@CURRENCY@',
'@TOTAL@',
'@BANK_DETAILS@',
]
def __init__(self, replace_vals: DocxInvoiceArg):
total = replace_vals.quantity * replace_vals.hourly
invoice_nr = replace_vals.project_name + datetime.datetime.strptime(replace_vals.date_to, '%Y-%m-%d').strftime('%Y%m%d')
self.replace_vals = [
{'search': self.tokens[0], 'replace': replace_vals.invoice_to },
{'search': self.tokens[1], 'replace': replace_vals.date_from },
{'search': self.tokens[2], 'replace': replace_vals.date_to },
{'search': self.tokens[3], 'replace': invoice_nr },
{'search': self.tokens[4], 'replace': replace_vals.project_name },
{'search': self.tokens[5], 'replace': replace_vals.quantity },
{'search': self.tokens[6], 'replace': replace_vals.hourly },
{'search': self.tokens[7], 'replace': replace_vals.currency },
{'search': self.tokens[8], 'replace': total },
{'search': self.tokens[9], 'replace': 'asdfasdfasdfdasf'},
]
self.doc_path_template = os.path.dirname(os.path.realpath(__file__))+'/docs/'
self.doc_path_output = self.doc_path_template + 'output/'
self.document: nDocument = Document(self.doc_path_template + 'invoice_placeholder.docx')
def save(self):
for p in self.document.paragraphs:
self._docx_replace_text(p)
tables = self.document.tables
self._loop_tables(tables)
self.document.save(self.doc_path_output + 'testiboi3.docx')
def _loop_tables(self, tables):
for table in tables:
for index, row in enumerate(table.rows):
for cell in table.row_cells(index):
if cell.tables:
self._loop_tables(cell.tables)
for p in cell.paragraphs:
self._docx_replace_text(p)
# for cells in column.
# for cell in table.columns:
def _docx_replace_text(self, p):
print(p.text)
for el in self.replace_vals:
if (el['search'] in p.text):
inline = p.runs
# Loop added to work with runs (strings with same style)
for i in range(len(inline)):
print(inline[i].text)
if el['search'] in inline[i].text:
text = inline[i].text.replace(el['search'], str(el['replace']))
inline[i].text = text
print(p.text)
Test case:
from django.test import SimpleTestCase
from docx.table import Table, _Rows
from toggleapi.services.DocxService import DocxService, DocxInvoiceArg
class TestDocxService(SimpleTestCase):
def test_document_read(self):
ds = DocxService(DocxInvoiceArg(invoice_to="""
WAW test1
Multi myfriend
""",date_from="2019-08-01", date_to="2019-08-30", project_name='WAW', quantity=10.5, hourly=40, currency='USD',bank_details="""
Paypal to:
bippo@bippsi.com"""))
ds.save()
have folders
docs
and
docs/output/
in same folder where you have DocxService.py
e.g.
be sure to parameterize and replace stuff
来源：https://stackoverflow.com/questions/24805671/how-to-use-python-docx-to-replace-text-in-a-word-document-and-save