问题
I have this sexy trigger, that takes a value from a field REFERENT, parses it, finds a row in some view and fills some data to original row that needs to be inserted. I also then re-write the REFERENT field and eliminate the extra data.
The REFERENT field looks like this: "-XXX-123", where 123 is the key that i search data in the view. Hope it makes sense.
CREATE OR REPLACE TRIGGER TRI_UPDATE
BEFORE INSERT
ON TBLASCENTOUTPUT_X
REFERENCING NEW AS NEW OLD AS OLD
FOR EACH ROW
WHEN (
new.STEVILKA_NAROCILA is NULL
)
DECLARE
PARSED_STNAROC VARCHAR(255);
PARSED_PRIMARY_VALUE VARCHAR(255);
BEGIN
PARSED_STNAROC := SUBSTR(NEW.REFERENT, INSTR(NEW.REFERENT, '-', -1, 1) + 1);
PARSED_PRIMARY_VALUE := SUBSTR(NEW.REFERENT, 1, INSTR(NEW.REFERENT, '-', -1, 1) - 1);
select distinct v.STNAROCILA, v.DATNAROCILA, v.SIFKUPCA, v.STPONUDBE, PARSED_PRIMARY_VALUE
into :NEW.STEVILKA_NAROCILA, :NEW.DATUM_NAROCILA, :NEW.SIFRA_KUPCA, :NEW.STEVILKA_PONUDBE, :NEW.REFERENT
from ARH_NAROC v
where v.STNAROCILA = PARSED_STNAROC;
END;
I am getting the following error on compile:
On line: 6
TRIGGER EASY.TRI_UPDATE
PLS-00201: identifier 'NEW.REFERENT' must be declared
Help please.
回答1:
A colon character is missed before NEW.REFERENT
来源：https://stackoverflow.com/questions/15542436/error-on-oracle-trigger