问题
I am trying to get an instance of a non-visible class, AKA package private class, using reflection. I was wondering if there was a way to switch the modifiers to make it public and then access it using Class.forName. When I try that now it stops me saying I can't do it. Unfortunately there is no setAccesible method of the Class class.
回答1:
nested class - class defined within other class (includes static and non-static classes)
inner class - non-static nested class (instance of inner class need instance of outer class to exist)
non-nested (top level) classes
Based on your question we know that constructor you want to access is not public. So your class may look like this (A class is in some package different than ours)
package package1;
public class A {
A(){
System.out.println("this is non-public constructor");
}
}
To create instance of this class we need to get to constructor we want to invoke, and make it accessible. When it is done we can use Constructor#newInstance(arguments) to create instance.
Class<?> c = Class.forName("package1.A");
//full package name --------^^^^^^^^^^
//or simpler without Class.forName:
//Class<package1.A> c = package1.A.class;
//In our case we need to use
Constructor<?> constructor = c.getDeclaredConstructor();
//note: getConstructor() can return only public constructors
//so we needed to search for any Declared constructor
//now we need to make this constructor accessible
constructor.setAccessible(true);//ABRACADABRA!
Object o = constructor.newInstance();
nested and inner classes
If you want to access nested (static and non-static) Class with Class.forName you need to use syntax:
Class<?> clazz = Class.forName("package1.Outer$Nested");
Outer$Nested says that Nested class is declared within Outer class. Nested classes are very similar to methods, they have access to all members of its outer class (including private ones).
But we need to remember that instance of inner class to exists requires instance of its outer class. Normally we create them via:
Outer outer = new Outer();
Outer.Inner inner = outer.new Inner();
so as you see each instance of Inner class have some information about its outer class (reference to that outer instance is stored in this$0 field, more info: What does it mean if a variable has the name "this$0" in IntelliJ IDEA while debugging Java?)
So while creating instance of Inner class with Constructor#newInstance() you need to pass as first argument reference to instance of Outer class (to simulate outer.new Inner() behavior).
Here is an example.
in package1
package package1;
public class Outer {
class Inner{
Inner(){
System.out.println("non-public constructor of inner class");
}
}
}
in package2
package package2;
import package1.Outer;
import java.lang.reflect.Constructor;
public class Test {
public static void main(String[] args) throws Exception {
Outer outerObject = new Outer();
Class<?> innerClazz = Class.forName("package1.Outer$Inner");
// constructor of inner class as first argument need instance of
// Outer class, so we need to select such constructor
Constructor<?> constructor = innerClazz.getDeclaredConstructor(Outer.class);
//we need to make constructor accessible
constructor.setAccessible(true);
//and pass instance of Outer class as first argument
Object o = constructor.newInstance(outerObject);
System.out.println("we created object of class: "+o.getClass().getName());
}
}
static-nested classes
Instances of static-nested classes don't require instance of Outer class (since they are static). So in their case we don't need to look for constructor with Outer.class as first argument. And we don't need to pass instance of outer class as first argument. In other words code will be same as for non-nested (top-level) class (maybe except fact that you would need to add $Nested syntax in Class.forName()).
回答2:
Class.forName should work. If the class is within a package hierarchy list in the "package.access" security property, then you will need to perform the operation with the appropriate privilege (usually all permissions; or don't have a security manager).
If you are trying to use Class.newInstance, don't. Class.newInstance handles exceptions poorly. Instead get a Constructor and call newInstance on that. It's difficult to see what you are having problems with without the exception trace.
As ever, most but not all uses of reflection are bad ideas.
回答3:
We recently released a library that helps a lot to access private fields, methods and inner classes through reflection : BoundBox
For a class like
public class Outer {
private static class Inner {
private int foo() {return 2;}
}
}
It provides a syntax like :
Outer outer = new Outer();
Object inner = BoundBoxOfOuter.boundBox_new_Inner();
new BoundBoxOfOuter.BoundBoxOfInner(inner).foo();
The only thing you have to do to create the BoundBox class is to write @BoundBox(boundClass=Outer.class) and the BoundBoxOfOuter class will be instantly generated.
回答4:
I had requirement to copy the value of field from older version of object if the value is null in latest version. We had these 2 options.
Core Java :
for (Field f : object.getClass().getSuperclass().getDeclaredFields()) {
f.setAccessible(true);
System.out.println(f.getName());
if (f.get(object) == null){
f.set(object, f.get(oldObject));
}
}
Using Spring [org.springframework.beans.BeanWrapper] :
BeanWrapper bw = new BeanWrapperImpl(object);
PropertyDescriptor[] data = bw.getPropertyDescriptors();
for (PropertyDescriptor propertyDescriptor : data) {
System.out.println(propertyDescriptor.getName());
Object propertyValue = bw.getPropertyValue(propertyDescriptor.getName());
if(propertyValue == null )
bw.setPropertyValue( new PropertyValue(propertyDescriptor.getName(),"newValue"));
}
回答5:
You can use Manifold's @Jailbreak for direct, type-safe Java reflection:
Foo foo = new @Jailbreak Foo();
public class Foo {
Foo() {...}
private void yodog() {...}
}
Here @Jailbreak enables the compiler to resolve the constructor type-safely as if public, while Manifold generates efficient reflection code for you under the hood.
Additionally you can use @Jailbreak to access and construct non-visible classes:
com.abc. @Jailbreak Bar bar = new com.abc. @Jailbreak Bar();
package com.abc;
// package-private class
class Bar {
Bar() {...}
}
For hidden class access, Java's annotation grammar requires the class to be annotated apart from its package.
More generally you can use @Jailbreak for any type of reflection:
@Jailbreak Foo foo = new Foo();
foo.yodog();
@Jailbreak unlocks the foo local variable in the compiler for direct access to all the members in Foo's hierarchy.
Similarly you can use the jailbreak() extension method for one-off use:
foo.jailbreak().yodog();
Through the jailbreak() method you can access any member in Foo's hierarchy.
Discover more about Manifold.
来源：https://stackoverflow.com/questions/15015675/accessing-non-visible-classes-with-reflection