问题
I am performing the following operations on lists of words. I read lines in from a Project Gutenberg text file, split each line on spaces, perform general punctuation substitution, and then print each word and punctuation tag on its own line for further processing later. I am unsure how to replace every single quote with a tag or excepting all apostrophes. My current method is to use a compiled regex:
apo = re.compile("[A-Za-z]'[A-Za-z]")
and perform the following operation:
if "'" in word and !apo.search(word):
word = word.replace("'","\n<singlequote>")
but this ignores cases where a single quote is used around a word with an apostrophe. It also does not indicate to me whether the single quote is abutting the start of a word of the end of a word.
Example input:
don't
'George
ma'am
end.'
didn't.'
'Won't
Example output (after processing and printing to file):
don't
<opensingle>
George
ma'am
end
<period>
<closesingle>
didn't
<period>
<closesingle>
<opensingle>
Won't
I do have a further question in relation to this task: since the distinguishment of <opensingle>
vs <closesingle>
seems rather difficult, would it be wiser to perform substitutions like
word = word.replace('.','\n<period>')
word = word.replace(',','\n<comma>')
after performing the replacement operation?
回答1:
What you really need to properly replace starting and ending '
is regex.
To match them you should use:
^'
for starting'
(opensingle),'$
for ending'
(closesingle).
Unfortunately, replace
method does not support regexes,
so you should use re.sub
instead.
Below you have an example program, printing your desired output (in Python 3):
import re
str = "don't 'George ma'am end.' didn't.' 'Won't"
words = str.split(" ")
for word in words:
word = re.sub(r"^'", '<opensingle>\n', word)
word = re.sub(r"'$", '\n<closesingle>', word)
word = word.replace('.', '\n<period>')
word = word.replace(',', '\n<comma>')
print(word)
回答2:
I suggest working smart here: use nltk's or another NLP toolkit instead.
Tokenize words like this:
import nltk
sentence = """At eight o'clock on Thursday morning
Arthur didn't feel very good."""
tokens = nltk.word_tokenize(sentence)
You may not like the fact that contractions like don't are separated. Actually, this is expected behavior. See Issue 401.
However, TweetTokenizer can help with that:
from nltk.tokenize import tknzr = TweetTokenizer()
tknzr.tokenize("The code didn't work!")
If it gets more involved a RegexpTokenizer could be helpful:
from nltk.tokenize import RegexpTokenizer
s = "Good muffins cost $3.88\nin New York. Please don't buy me\njust one of them."
tokenizer = RegexpTokenizer('\w+|\$[\d\.]+|\S+')
tokenizer.tokenize(s)
Then it should be much easier to annotate the tokenized words correctly.
Further references:
- http://www.nltk.org/api/nltk.tokenize.html
- http://www.nltk.org/_modules/nltk/tokenize/regexp.html
回答3:
I think this can benefit from lookahead or lookbehind references. The python reference is https://docs.python.org/3/library/re.html, and one generic regex site I often reference is https://www.regular-expressions.info/lookaround.html.
Your data:
words = ["don't",
"'George",
"ma'am",
"end.'",
"didn't.'",
"'Won't",]
And now I'll define a tuple with regular expressions and their replacements.
In [230]: apo = (
(re.compile("(?<=[A-Za-z])'(?=[A-Za-z])"), "<apostrophe>",),
(re.compile("(?<![A-Za-z])'(?=[A-Za-z])"), "<opensingle>",),
(re.compile("(?<=[.A-Za-z])'(?![A-Za-z])"), "<closesingle>", ),
(re.compile("(?<=[A-Za-z])\\.(?![A-Za-z])"), "<period>",),
)
...: ...: ...: ...: ...: ...:
In [231]: words = ["don't",
"'George",
"ma'am",
"end.'",
"didn't.'",
"'Won't",]
...: ...: ...: ...: ...: ...:
In [232]: reduce(lambda w2,x: [ x[0].sub(x[1], w) for w in w2], apo, words)
Out[232]:
['don<apostrophe>t',
'<opensingle>George',
'ma<apostrophe>am',
'end<period><closesingle>',
'didn<apostrophe>t<period><closesingle>',
'<opensingle>Won<apostrophe>t']
Here's what's going on with the regexes:
(?<=[A-Za-z])
is a lookbehind, meaning only match (but do not consume) if the preceding character is a letter.(?=[A-Za-z])
is a lookahead (still no consume) if the following character is a letter.(?<![A-Za-z])
is a negative lookbehind, meaning if there is a letter preceding it, then it will not match.(?![A-Za-z])
is a negative lookahead.
Note that I added a .
check within <closesingle>
, and the order within apo
matters, because you might be replacing .
with <period>
...
This was operating on single words, but should work with sentences as well.
In [233]: onelong = """
don't
'George
ma'am
end.'
didn't.'
'Won't
"""
...: ...: ...: ...: ...: ...: ...:
In [235]: print(
reduce(lambda sentence,x: x[0].sub(x[1], sentence), apo, onelong)
)
...: ...:
don<apostrophe>t
<opensingle>George
ma<apostrophe>am
end<period><closesingle>
didn<apostrophe>t<period><closesingle>
<opensingle>Won<apostrophe>t
(The use of reduce
is to facilitate applying a regex's .sub
on the words/strings and then keep that output for the next regex's .sub
, etc.)
来源:https://stackoverflow.com/questions/50777729/python-replace-single-quotes-except-apostrophes