问题
As per my knowledge, segmentation for c program is:
High address
|---------------------------|
|env/cmd line args vars |
|---------------------------|
| stack segment |--> uninitialized auto vars
|---------------------------|
|---------------------------|
|---------------------------|
| heap segment |--> dynamic allocated memory
|---------------------------|
| BSS segment |--> uninitialized static/global vars
|---------------------------|
| data segment |--> initialized static/global vars
|---------------------------|
| text segment |--> initialized auto vars/exec instructions
|---------------------------|
Low address
On my RHEL 5.4 64-bit machine, for below c program
#include <stdio.h>
int main()
{
}
when I do:
# size a.out
text data bss dec hex filename
1259 540 16 1815 717 a.out
I am unable to understand why is
bss=16
As I am not declaring/initializing any global/static vars?
回答1:
It's worse on Windows with gcc:
main.c:
#include <stdio.h>
int main( int argc, char* argv[] )
{
return 0;
}
compile:
C:\>gcc main.c
size:
C:\>size a.exe
text data bss dec hex filename
6936 1580 1004 9520 2530 a.exe
bss includes the whole linked executable and in this case various libraries are linked in which do use static c initialisation.
Using -nostartfiles gets a much better result on windows. You can also try with -nostdlib and -nodefaultlibs
compile:
C:\>gcc -nostartfiles main.c
size:
C:\>size a.exe
text data bss dec hex filename
488 156 32 676 2a4 a.exe
Remove all the libraries (including the c library) and you get an "executable" with exactly what you've compiled and a bss size of 0:
main.c:
#include <stdio.h>
int _main( int argc, char* argv[] )
{
return 0;
}
compile:
C:\>gcc -nostartfiles -nostdlib -nodefaultlibs main.c
size:
C:\>size a.exe
text data bss dec hex filename
28 20 0 48 30 a.exe
The executable won't run however!
来源:https://stackoverflow.com/questions/28962014/why-bss-segment-is-16-by-default