Considering this code:
public class Foo
{
public int a { get; set; }
public int b { get; set; }
}
private void Test()
{
List<Foo> foos = new List<Foo>();
foos.Add(new Foo());
foos.Add(new Foo());
Expression<Func<Foo, int>> exp0 = f => f.a * f.b;
Expression<Func<int>> exp1 = () => foos[0].a * foos[0].b;
Expression<Func<int>> exp2 = () => foos[1].a * foos[1].b;
}
How can you take exp0
and turn it into two expressions identical to exp1
and exp2
. Note that I don't want to just evaluate exp0
for each Foo
in foos
, but instead get two new expressions.
[Update]:
Basically, I want to be able to expand or "flatten" an expression passed to a Linq
extension method such as Sum
into one expression per item in the enumeration since these enumerations will be static, and because I already have code that reads expressions that don't take parameters (and then turns them into another language).
I'm using the MetadataToken
as a references to properties that have a certain attribute (in this case a
and b
would have this attribute) and using it with a dictionary that correlates C# properties to another language's variables:
Foo foo = new Foo();
Expression<Func<int>> exp = () => foo.a * foo.a + foo.b;
string result1 = GetResult(exp); // gets "v_001 * v_001 + v_002"
List<Foo> foes = new List<Foo>();
foes.Add(new Foo());
foes.Add(new Foo());
Expression<Func<int>> exp2 = () => foes.Sum(f => f.a * f.a + f.b);
string result2 = GetResult(exp2); // should get "(v_001 * v_001 + v_002) + (v_003 * v_003 + v_004)"
I would do it this way:
Write a parameter-replacer expression-visitor that manipulates the original expression as follows:
- Gets rid of the parameter you don't want entirely from the lambda signature.
- Replaces all uses of the parameter with the desired indexer expression.
Here's a quick and dirty sample I whipped up based on my earlier answer on a different question:
public static class ParameterReplacer
{
// Produces an expression identical to 'expression'
// except with 'source' parameter replaced with 'target' expression.
public static Expression<TOutput> Replace<TInput, TOutput>
(Expression<TInput> expression,
ParameterExpression source,
Expression target)
{
return new ParameterReplacerVisitor<TOutput>(source, target)
.VisitAndConvert(expression);
}
private class ParameterReplacerVisitor<TOutput> : ExpressionVisitor
{
private ParameterExpression _source;
private Expression _target;
public ParameterReplacerVisitor
(ParameterExpression source, Expression target)
{
_source = source;
_target = target;
}
internal Expression<TOutput> VisitAndConvert<T>(Expression<T> root)
{
return (Expression<TOutput>)VisitLambda(root);
}
protected override Expression VisitLambda<T>(Expression<T> node)
{
// Leave all parameters alone except the one we want to replace.
var parameters = node.Parameters
.Where(p => p != _source);
return Expression.Lambda<TOutput>(Visit(node.Body), parameters);
}
protected override Expression VisitParameter(ParameterExpression node)
{
// Replace the source with the target, visit other params as usual.
return node == _source ? _target : base.VisitParameter(node);
}
}
}
Usage for your scenario (tested):
var zeroIndexIndexer = Expression.MakeIndex
(Expression.Constant(foos),
typeof(List<Foo>).GetProperty("Item"),
new[] { Expression.Constant(0) });
// .ToString() of the below looks like the following:
// () => (value(System.Collections.Generic.List`1[App.Foo]).Item[0].a
// * value(System.Collections.Generic.List`1[App.Foo]).Item[0].b)
var exp1Clone = ParameterReplacer.Replace<Func<Foo, int>, Func<int>>
(exp0, exp0.Parameters.Single(), zeroIndexIndexer);
来源:https://stackoverflow.com/questions/11159697/replace-parameter-in-lambda-expression