问题
It's basically returning the boxes_needed. 1 box can contain 10 items. So if the items typed by the user is 102 then the code should return 11 boxes.
Is there a way to divide that rounds upwards if there is a non-zero remainder?
回答1:
For your use case, use integer arithmetic. There is a simple technique for converting integer floor division into ceiling division:
items = 102
boxsize = 10
num_boxes = (items + boxsize - 1) // boxsize
Alternatively, use negation to convert floor division to ceiling division:
num_boxes = -(items // -boxsize)
回答2:
Negate before and after?
>>> -(-102 // 10)
11
回答3:
from math import ceil
print(ceil(10.3))
11
回答4:
You can try :
import math
math.ceil( x )
来源：https://stackoverflow.com/questions/33299093/how-to-perform-ceiling-division-in-integer-arithmetic