问题
I have a method that accepts default arguments:
def build_url(endpoint, host=settings.DEFAULT_HOST):
return '{}{}'.format(host, endpoint)
I have a test case that exercises this method:
class BuildUrlTestCase(TestCase):
def test_build_url(self):
""" If host and endpoint are supplied result should be 'host/endpoint' """
result = build_url('/end', 'host')
expected = 'host/end'
self.assertEqual(result,expected)
@patch('myapp.settings')
def test_build_url_with_default(self, mock_settings):
""" If only endpoint is supplied should default to settings"""
mock_settings.DEFAULT_HOST = 'domain'
result = build_url('/end')
expected = 'domain/end'
self.assertEqual(result,expected)
If I drop a debug point in build_url
and inspect this attribute settings.DEFAULT_HOST
returns the mocked value. However the test continues to fail and the assertion indicates host
is assigned the value from my actual settings.py
. I know this is because the host
keyword argument is set at import time and my mock is not considered.
debugger
(Pdb) settings
<MagicMock name='settings' id='85761744'>
(Pdb) settings.DEFAULT_HOST
'domain'
(Pdb) host
'host-from-settings.com'
Is there a way to override this value at test time so that I can exercise the default path with a mocked settings
object?
回答1:
Functions store their parameter default values in the func_defaults
attribute when the function is defined, so you can patch that. Something like
def test_build_url(self):
""" If only endpoint is supplied should default to settings"""
# Use `func_defaults` in Python2.x and `__defaults__` in Python3.x.
with patch.object(build_url, 'func_defaults', ('domain',)):
result = build_url('/end')
expected = 'domain/end'
self.assertEqual(result,expected)
I use patch.object
as a context manager rather than a decorator to avoid the unnecessary patch object being passed as an argument to test_build_url
.
回答2:
I applied the other answer to this question, but after the context manager, the patched function was not the same as before.
My patched function looks like this:
def f(foo=True):
pass
In my test, I did this:
with patch.object(f, 'func_defaults', (False,)):
When calling f
after (not in) the context manager, the default was completely gone rather than going back to the previous value. Calling f
without arguments gave the error TypeError: f() takes exactly 1 argument (0 given)
Instead, I just did this before my test:
f.func_defaults = (False,)
And this after my test:
f.func_defaults = (True,)
回答3:
An alternate way to do this: Use functools.partial to provide the "default" args you want. This isn't technically the same thing as overriding them; the call-ee sees an explicit arg, but the call-er doesn't have to provide it. That's close enough most of the time, and it does the Right Thing after the context manager exits:
# mymodule.py
def myfunction(arg=17):
return arg
# test_mymodule.py
from functools import partial
from mock import patch
import mymodule
class TestMyModule(TestCase):
def test_myfunc(self):
patched = partial(mymodule.myfunction, arg=23)
with patch('mymodule.myfunction', patched):
self.assertEqual(23, mymodule.myfunction()) # Passes; default overridden
self.assertEqual(17, mymodule.myfunction()) # Also passes; original default restored
I use this for overriding default config file locations when testing. Credit where due, I got the idea from Danilo Bargen here
来源:https://stackoverflow.com/questions/24021491/python-unittest-mock-is-it-possible-to-mock-the-value-of-a-methods-default-arg